A. java中怎麼把文件上傳到伺服器的指定路徑
文件從本地到伺服器的功能，其實是為了解決目前瀏覽器不支持獲取本地文件全路徑。不得已而想到上傳到伺服器的固定目錄，從而方便項目獲取文件，進而使程序支持EXCEL批量導入數據。
java中文件上傳到伺服器的指定路徑的代碼：
在前台界面中輸入：
<form method="post" enctype="multipart/form-data" action="../manage/excelImport.do">
請選文件:<input type="file" name="excelFile">
<input type="submit" value="導入" onclick="return impExcel();"/>
</form>
action中獲取前台傳來數據並保存
/**
* excel 導入文件明頌
* @return
* @throws IOException
*/
@RequestMapping("/usermanager/excelImport.do")
public String excelImport(
String filePath,
MultipartFile excelFile,HttpServletRequest request) throws IOException{
log.info("<<悉孫<<<<action:{} Method:{} start>>>>>>","usermanager","excelImport" );
if (excelFile != null){
String filename=excelFile.getOriginalFilename();
String a=request.getRealPath("u/cms/www/201509");
SaveFileFromInputStream(excelFile.getInputStream(),request.getRealPath("u/cms/www/201509"),filename);//保存到服激陸鄭務器的路徑
}
log.info("<<<<<<action:{} Method:{} end>>>>>>","usermanager","excelImport" );
return "";
}
/**
* 將MultipartFile轉化為file並保存到伺服器上的某地
*/
public void SaveFileFromInputStream(InputStream stream,String path,String savefile) throws IOException
{
FileOutputStream fs=new FileOutputStream( path + "/"+ savefile);
System.out.println("------------"+path + "/"+ savefile);
byte[] buffer =new byte[1024*1024];
int bytesum = 0;
int byteread = 0;
while ((byteread=stream.read(buffer))!=-1)
{
bytesum+=byteread;
fs.write(buffer,0,byteread);
fs.flush();
}
fs.close();
stream.close();
}
B. java帶參帶進度條（真實）上傳文件代碼
思路如下：
public class MyClass extends Thread {
public JProgressBar bar = new JProgressBar();//進度條
public OutputStream os;// 通向伺服器的流
public InputStream is;// 你的文件流
public long len;// 你文件的總長度
public void run() {
byte[] buff = new byte[1024];
long passedlen = 0;
try {
int mark = 0;
while (true) {
mark = is.read(buff, 0, 1024);
os.write(buff, 0, mark);
// 更新進度
passedlen += mark;
int prog = (int) ((double) passedlen / (len == 0 ? 1 : len) * 100);
// 改變進度條的value值
bar.setValue(prog);
// 結束判定
if (passedlen == len) {
break;
}
}
os.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
C. java如何實現文件上傳
public static int transFile(InputStream in, OutputStream out, int fileSize) {
int receiveLen = 0;
final int bufSize = 1000;
try {
byte[] buf = new byte[bufSize];
int len = 0;
while(fileSize - receiveLen > bufSize)
{
len = in.read(buf);
out.write(buf, 0, len);
out.flush();
receiveLen += len;
System.out.println(len);
}
while(receiveLen < fileSize)
{
len = in.read(buf, 0, fileSize - receiveLen);
System.out.println(len);
out.write(buf, 0, len);
receiveLen += len;
out.flush();
}
} catch (IOException e) {
// TODO 自動生成 catch 塊
e.printStackTrace();
}
return receiveLen;
}
這個方法從InputStream中讀取內容，寫到OutputStream中。
那麼發送文件方，InputStream就是FileInputStream，OutputStream就是Socket.getOutputStream.
接受文件方，InputStream就是Socket.getInputStream,OutputStream就是FileOutputStream。
就OK了。 至於存到資料庫里嘛，Oracle里用Blob。搜索一下，也是一樣的。從Blob能獲取一個輸出流。
D. 用Java的三大框架實現文件的上傳下載，求代碼啊，最好是分為action,service,serv
package cn.itcast.struts2.demo1;
import java.io.File;
import org.apache.commons.io.FileUtils;
import org.apache.struts2.ServletActionContext;
import com.opensymphony.xwork2.ActionSupport;
/**
* 完成文件上傳 （不是解析上傳內容，因為上傳內容 由fileUpload攔截器負責解析）
*
* @author seawind
*
*/
public class UploadAction extends ActionSupport {
// 接收上傳內容
// <input type="file" name="upload" />
private File upload; // 這里變數名 和 頁面表單元素 name 屬性一致
private String uploadContentType;
private String uploadFileName;
public void setUpload(File upload) {
this.upload = upload;
}
public void setUploadContentType(String uploadContentType) {
this.uploadContentType = uploadContentType;
}
public void setUploadFileName(String uploadFileName) {
this.uploadFileName = uploadFileName;
}
@Override
public String execute() throws Exception {
if (upload == null) { // 通過xml配置 required校驗器 完成校驗
// 沒有上傳文件
return NONE;
}
// 將上傳文件 保存到伺服器端
// 源文件 upload
// 目標文件
File destFile = new File(ServletActionContext.getServletContext()
.getRealPath("/upload") + "/" + uploadFileName);
// 文件復制 使用commons-io包 提供 工具類
FileUtils.File(upload, destFile);
return NONE;
}
}
多文件上傳
package cn.itcast.struts2.demo1;
import java.io.File;
import org.apache.commons.io.FileUtils;
import org.apache.struts2.ServletActionContext;
import com.opensymphony.xwork2.ActionSupport;
/**
* 支持多文件上傳
*
* @author seawind
*
*/
public class MultiUploadAction extends ActionSupport {
// 接收多文件上傳參數，提供數組接收就可以了
private File[] upload;
private String[] uploadContentType;
private String[] uploadFileName;
public void setUpload(File[] upload) {
this.upload = upload;
}
public void setUploadContentType(String[] uploadContentType) {
this.uploadContentType = uploadContentType;
}
public void setUploadFileName(String[] uploadFileName) {
this.uploadFileName = uploadFileName;
}
@Override
public String execute() throws Exception {
for (int i = 0; i < upload.length; i++) {
// 循環完成上傳
File srcFile = upload[i];
String filename = uploadFileName[i];
// 定義目標文件
File destFile = new File(ServletActionContext.getServletContext()
.getRealPath("/upload" + "/" + filename));
FileUtils.File(srcFile, destFile);
}
return NONE;
}
}
E. java實現文件上傳，代碼盡量簡潔~~~~~·
你說的2種方法都是很簡單的，參考網上的資料都不難做出，用io流做更是基礎中的基礎，我說下smartupload好了，有的人是直接寫在jsp上面，感覺比較亂，我一般都是寫在action裡面，打好jar包和配置後
SmartUpload mySmartUpload = new SmartUpload();
//如果是struts2.0或者webwork 則是mySmartUpload.initialize(ServletActionContext.getServletConfig(),ServletActionContext.getRequest(),ServletActionContext.getResponse());
mySmartUpload.initialize(servlet.getServletConfig(), request,response);
mySmartUpload.setTotalMaxFileSize(500000);
//如果上傳任意文件不設置mySmartUpload.setAllowedFilesList（文件後綴名）就可以了
mySmartUpload.upload();
for (int i = 0; i < mySmartUpload.getFiles().getCount(); i++) {
com.jspsmart.upload.File file = mySmartUpload.getFiles().getFile(i);
if (file.isMissing()) continue;
file.saveAs(保存的地址 + file.getFileName(),
su.SAVE_PHYSICAL);