java編程習題集

⑴ 有關java編程題目

按照題目要求編寫的圓,圓錐和測試類的Java程序如下

Test.java文件內容如下

class Circle{

private double r;

private String color;

public Circle(double r){

this.r=r;

}

public double area(){

return Math.PI*r*r;

}

public double perimeter(){

return Math.PI*2*r;

}

public double getR(){

return this.r;

}

public void setR(double r){

this.r=r;

}

public String getColor(){

return this.color;

}

public void setColor(String color){

this.color=color;

}

public String toString(){

return "圓的半徑為"+r+",顏色為"+color;

}

}

class Cone{

private Circle c;

private double h;

private String color;

public Cone(Circle c,double h){

this.c=c;

this.h=h;

}

public double volume(){

return 1.0/3*c.area()*h;

}

public Circle getCircle(){

return this.c;

}

public void setCircle(Circle c){

this.c=c;

}

public double getH(){

return this.h;

}

public void setH(double h){

this.h=h;

}

public String getColor(){

return this.color;

}

public void setColor(String color){

this.color=color;

}

public String toString(){

return "圓錐的底面積為"+c.area()+",高為"+h+",顏色為"+color;

}

}

public class Test{

public static void main(String[] args){

Circle circle1=new Circle(2.5);

circle1.setColor("紅色");

System.out.println(circle1.toString());

System.out.println("圓的面積為"+circle1.area());

System.out.println("圓的周長為"+circle1.perimeter());

Cone circlar1=new Cone(circle1,2.7);

circlar1.setColor("藍色");

System.out.println(circlar1.toString());

System.out.println("圓錐的體積為"+circlar1.volume());

}

}

⑵ 五道java語言描述的數據結構編程題，請求給予詳細解答

第一題：

//使用集合提供的工具方法
public static List<Integer> merge(List<Integer> a, List<Integer> b) {
//a,b not null
//全部放到一個set裡面，使得元素合並
Set<Integer> set = new HashSet<Integer>(a);
set.addAll(b);
//將set裡面的元素放到列表再轉為數組
Integer[] array = new ArrayList<Integer>(set).toArray(new Integer[1]);
//升序排序
Arrays.sort(array);
//將排序後的數組轉為list
return Arrays.asList(array);
}

//自己寫的演算法， a為升序列表，b為降序列表
public static List<Integer> merge2(List<Integer> a, List<Integer> b) {
//a,b not null
int aSize = a.size();
int bSize = b.size();
List<Integer> result = new ArrayList<Integer>();
int aIndex = 0;// 升序列表從首位開始
int bIndex = bSize - 1;// 降序列表從末尾開始
int aEl;
int bEl;
// 循環終止條件為: a 或者 b 列表遍歷完
while (aIndex < aSize && bIndex >= 0) {
aEl = a.get(aIndex);
bEl = b.get(bIndex);
if (aEl < bEl) {
result.add(aEl);
aIndex++;
} else {
result.add(bEl);
bIndex--;
}
}
// 將某個未遍歷完的列表中的元素添加到結果(包括了任意一個列表為空列表的情況)
if (aIndex < aSize) {
for (int i = aIndex; i < aSize; i++) {
result.add(a.get(i));
}
}
else if (bIndex > 0) {
for (int i = bIndex; i >= 0; i--) {
result.add(b.get(i));
}
}
return result;
}

⑶ 100分,幾道簡單的Java編程題，幫忙解決一下！

不是我牛叉
以前有過類似的練習
修改了一陪冊乎下就姿褲發了
我也同意樓下的觀點 自己動手做一下
有什麼不明白的可以參考我的這個
也許你有更好的解決方法
1.
import java.util.Scanner;
public class Test_If_Switch
{
public static void main(String[] args) {
System.out.println("輸入一個數字:");
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
System.out.println("方法1:"+methodl(x));
System.out.println("方法2:"+method2(x));
}
static int methodl(int x)
{
int result = 0;
if(x<0)
result = 2*x-1;
else if(x>=0&&x<3)
result = 3*x+5;
else if(x>=3&&x<5)
result = x+1;
else if(x>=5&&x<10)
result=5*x-3;
else if(x>=10)
result = 7*x+2;
return result;
}

static int method2(int x)
{
int result = 0;
switch(x)
{
case 0:
case 1:
case 2:result = 3*x+5;break;
case 3:
case 4:result = x+1;break;
case 5:
case 6:
case 7:
case 8:
case 9:result=5*x-3;break;
case 10:result = 7*x+2;break;
default:result = 2*x-1;break;
}
return result;
}
}

2.
import java.util.Scanner;

public class Test_Tn {
public static void main(String[] args) {
System.out.println("輸入一個數字:");
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
System.out.println("第"+x+"項的值為:"+method(x));

}

static long static method(int n) {
long Tn = 0;
if (x == 1)
Tn = 1;
else
Tn = method(x - 1) + x;
return Tn;
}
}

3.
public class test
{
public static void main (String args[])
{
int n=100;
while(n<=1000)
{
int i,j,k;
i=n/100;
j=(n-i*100)/10;
k=n%10;
if((Math.pow(i, 3)+Math.pow(j, 3)+Math.pow(k, 3))==n)

System.out.print(n+String.valueOf('\t'));
n++;
}
}
}

4.
public class Money {
public static void main(String[] args)
{
int a = 100,b = 50, c =10;
for(int i =5;i<=8;i++)
for(int j = 0;j<=6;j++)
for(int k = 0;k<30;k++)
{
if(a*i+b*j+c*k==800)
System.out.println("蘆悉100元"+i+"張"+"50元"+j+"張"+"10元"+k+"張");
}

}
}