1. 基於51單片機的簡易計算器製作
您好,這樣的:
縱觀單片機的發展過程,可以預示單片機的發展趨勢,;1)低功耗CMOS化;MCS-51系列的8051推出時的功耗達630m;2)微型單片化;現在常規的單片機普遍都是將中央處理器(CPU)、;此外,現在的產品普遍要求體積
照程序設計的各部分實現的功能不同,將整個軟體系統分成了三個塊,並對每一個功能塊所採用的元器件進行了詳細介紹。此外還編寫了主要功能模塊的基本程序,詳盡闡述了各模塊的工作過程。還有總流程圖,源代碼,硬器件鋪線圖。
2. 學會51單片機可以自己做什麼小東西
可以玩的東西非常的多,時鍾、鬧鍾、各種定時控制、通過手機Wifi對家電實施遠程式控制制、通過手機藍牙的遙控、無線遙控,不勝枚舉。
3. 怎樣用51單片機做計算器啊
1、硬體模擬圖
4、程序源代碼
#include <reg51.h>#include <intrins.h>
#include <ctype.h>
#include <stdlib.h>
#define uchar unsigned char
#define uint unsigned int
uchar operand1[9], operand2[9];
uchar operator;
void delay(uint);
uchar keyscan();
void disp(void);
void buf(uint value);
uint compute(uint va1,uint va2,uchar optor);
uchar code table[] = {0xc0,0xf9,0xa4,0xb0,0x99,
0x92,0x82,0xf8,0x80,0x90,0xff};
uchar dbuf[8] = {10,10,10,10,10,10,10,10};
void delay(uint z)
{
uint x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}
uchar keyscan()
{
uchar skey;
P1 = 0xfe;
while((P1 & 0xf0) != 0xf0)
{
delay(3);
while((P1 & 0xf0) != 0xf0)
{
switch(P1)
{
case 0xee: skey = '7'; break;
case 0xde: skey = '8'; break;
case 0xbe: skey = '9'; break;
case 0x7e: skey = '/'; break;
default: skey = '#';
}
while((P1 & 0xf0) != 0xf0)
;
}
}
P1 = 0xfd;
while((P1 & 0xf0) != 0xf0)
{
delay(3);
while((P1 & 0xf0) != 0xf0)
{
switch(P1)
{
case 0xed: skey = '4'; break;
case 0xdd: skey = '5'; break;
case 0xbd: skey = '6'; break;
case 0x7d: skey = '*'; break;
default: skey = '#';
}
while((P1 & 0xf0) != 0xf0)
;
}
}
P1 = 0xfb;
while((P1 & 0xf0) != 0xf0)
{
delay(3);
while((P1 & 0xf0) != 0xf0)
{
switch(P1)
{
case 0xeb: skey = '1'; break;
case 0xdb: skey = '2'; break;
case 0xbb: skey = '3'; break;
case 0x7b: skey = '-'; break;
default: skey = '#';
}
while((P1 & 0xf0) != 0xf0)
;
}
}
P1 = 0xf7;
while((P1 & 0xf0) != 0xf0)
{
delay(3);
while((P1 & 0xf0) != 0xf0)
{
switch(P1)
{
case 0xe7: skey = '$'; break;
case 0xd7: skey = '0'; break;
case 0xb7: skey = '='; break;
case 0x77: skey = '+'; break;
default: skey = '#';
}
while((P1 & 0xf0) != 0xf0)
;
}
}
return skey;
}
void main()
{
uint value1, value2, value;
uchar ckey, cut1 = 0, cut2 = 0;
uchar operator;
uchar i, bool = 0;
init:
buf(0);
disp();
value = 0;
cut1 = cut2 = 0;
bool = 0;
for(i = 0;i < 9;i++)
{
operand1[i] = '