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c库源码

发布时间:2022-01-31 22:27:20

linux下怎么查看c函数库的源代码

头文件在/usr/include/sys/time.h

如果要看定义,下载glibc的源代码。

⑵ c标准库中的源码实现细节需要看懂吗

库函数的实现细节源码不需要完全看的东,作为一个程序员,首先需要掌握的是库函数的功能、语法和用法。
至于库函数的实现细节,可等有了基础之后再去搞明白就可以了。搞明白哪些对自己的编程也是很有帮助的。

⑶ c语言仓库管理系统源代码你有吗

学籍管理的程序,你自己改改吧
#include<stdio.h>
#include<windows.h>
#include<conio.h>
int add();
int amend();
int remove();
int show_student();
int show_class();
struct info //定义结构体info,用于存储学生信息
{
char name[20]; //姓名
char sex[20]; //性别
char idcard[20]; //身份证号码
char stuid[10]; //学号
char academe[20]; //学院
char specialty[20]; //专业
char classid[20]; //班级
char home[20]; //生源地
}stu[100];
int j=0;
int main(void) //主函数
{
/*登陆界面设计*/
char gongnengxuanzhe;
int flag=1;
system("cls");
printf("\n");
printf("\t\t\t\t 欢迎\n");
printf("\n\n\t尊敬的用户, 非常感谢您使用本系统 , 您的完美体验将是我们前进的方向 !\n\n\n");
printf("\t系统功能简介:\n\n\n");
printf("\t\t①:通过键盘输入某位学生的学生证信息。\n\n");
printf("\t\t②:给定学号,显示某位学生的学生证信息。\n\n");
printf("\t\t③:给定某个班级的班号,显示该班所有学生的学生证信息。\n\n");
printf("\t\t④:给定某位学生的学号,修改该学生的学生证信息。\n\n");
printf("\t\t⑤:给定某位学生的学号,删除该学生的学生证信息。\n\n");
printf("\t\t⑥:按出生日期对全班学生的信息进行排序。\n\n\n");
printf("\t按任意键进入系统......");
getch();
do
{
system("cls");
printf("\n\n\n");
printf(" 尊敬的用户 ,欢迎您使用本系统 !\n");
printf("\n\n\n");
printf(" 1.增加学生信息\n\n");
printf(" 2.修改学生信息\n\n");
printf(" 3.删除学生信息\n\n");
printf(" 4.显示单个学生信息\n\n");
printf(" 5.显示整个班级学生信息\n\n");
printf(" 0.退出系统\n\n\n\n");
printf(" 请选择您需要使用的功能:");
gongnengxuanzhe=getch();
switch(gongnengxuanzhe)
{
case '1':add();break;
case '2':amend();break;
case '3':remove();break;
case '4':show_student();break;
case '5':show_class();break;
case '0':flag=0;break;
default:
{
printf("\n\n 您的输入有误,请仔细阅读使用说明!");
printf("\n 任意键继续...");
getch();
}

}
}while(flag==1);
system("cls");
printf("\n\n\n\n\n\n\n\n\n\n\t尊敬的用户,非常感谢您的使用,您对于完美的追求是我们唯一的动力!");
printf("\n\n\t\t\t 按任意键退出系统......");
getch();
return 0;
}
int add() //增加学生信息函数
{
char flag='1';
do
{
system("cls");
printf("\n\t姓名:");
scanf("%s",&stu[j].name);
printf("\n\n\t性别:");
scanf("%s",&stu[j].sex);
printf("\n\n\t身份证号:");
scanf("%s",&stu[j].idcard);
printf("\n\n\t学院:");
scanf("%s",&stu[j].academe);
printf("\n\n\t专业:");
scanf("%s",&stu[j].specialty);
printf("\n\n\t班级:");
scanf("%s",&stu[j].classid);
printf("\n\n\t学号:");
scanf("%s",&stu[j].stuid);
printf("\n\n\t生源地:");
scanf("%s",&stu[j].home);
j++;
printf("\n\t继续增加请键入1,返回请键入其他任意键:");
getchar();
flag=getchar();
}while(flag=='1');
return 0;
}
int amend() //修改学生信息函数
{
if(j==0)
{
system("cls");
printf("\n\n\n\n\n\n\n\n\n\n\t\t 系统无任何可以修改的记录,请先行输入数据!");
printf("\n\n\t\t\t 按任意键返回......");
getch();
return 0;
}
char a[20];
int z;
int flag=0;
do
{
system("cls");
printf("\n\t需要修改的学生学号:");
scanf("%s",a);
for(z=0;z<j;z++)
{
if(strcmp(stu[z].stuid,a)==0)
{
flag=1;
break; //break退出后,z++不会执行
}
}
if(flag==0)
{
printf("\t对不起,你请求学生信息不存在,请核实后重试!\n");
printf("\t按任意键继续......");
getch();
}
}while(flag==0);
system("cls");
printf("\n\t姓名:");
scanf("%s",&stu[z].name);
printf("\n\n\t性别:");
scanf("%s",&stu[z].sex);
printf("\n\n\t身份证号:");
scanf("%s",&stu[z].idcard);
printf("\n\n\t学院:");
scanf("%s",&stu[z].academe);
printf("\n\n\t专业:");
scanf("%s",&stu[z].specialty);
printf("\n\n\t班级:");
scanf("%s",&stu[z].classid);
printf("\n\n\t学号:");
scanf("%s",&stu[z].stuid);
printf("\n\n\t生源地:");
scanf("%s",&stu[z].home);
return 0;
}
int remove() //删除学生信息函数
{
if(j==0)
{
system("cls");
printf("\n\n\n\n\n\n\n\n\n\n\t\t 系统无任何可以删除的记录,请先行输入数据!");
printf("\n\n\t\t\t 按任意键返回......");
getch();
return 0;
}
char a[20];
int z;
int x;
int flag=0;
do
{
system("cls");
printf("\n\t需要删除的学生学号:");
scanf("%s",a);
for(z=0;z<j;z++)
{
if(strcmp(stu[z].stuid,a)==0)
{
flag=1;
for(x=z;x<j;x++)
{
strcpy(stu[x].name,stu[x+1].name);
strcpy(stu[x].sex,stu[x+1].sex);
strcpy(stu[x].idcard,stu[x+1].idcard);
strcpy(stu[x].academe,stu[x+1].academe);
strcpy(stu[x].specialty,stu[x+1].specialty);
strcpy(stu[x].classid,stu[x+1].classid);
strcpy(stu[x].stuid,stu[x+1].stuid);
strcpy(stu[x].stuid,stu[x+1].stuid);
}
j--;
printf("\n\t删除成功!");
printf("\n\t按任意键返回上级菜单......");
getch();
}
}
if(flag==0)
{
printf("\t对不起,你请求学生信息不存在,请核实后重试!\n");
printf("\t按任意键继续......");
getch();
}
}while(flag==0);
return 0;
}
int show_student() //单个显示学生信息函数
{
if(j==0)
{
system("cls");
printf("\n\n\n\n\n\n\n\n\n\n\t\t 系统无任何可以显示的记录,请先行输入数据!");
printf("\n\n\t\t\t 按任意键返回......");
getch();
return 0;
}
char a[20];
int z;
int flag=0;
do
{
system("cls");
printf("\n\t需要显示的学生学号:");
scanf("%s",a);
for(z=0;z<j;z++)
{
if(strcmp(stu[z].stuid,a)==0)
{
flag=1;
system("cls");
printf("\n\t姓名:%s",stu[z].name);
printf("\n\n\t性别:%s",stu[z].sex);
printf("\n\n\t身份证号:%s",stu[z].idcard);
printf("\n\n\t学院:%s",stu[z].academe);
printf("\n\n\t专业:%s",stu[z].specialty);
printf("\n\n\t班级:%s",stu[z].classid);
printf("\n\n\t学号:%s",stu[z].stuid);
printf("\n\n\t生源地:%s",stu[z].home);
printf("\n\n\t按任意键返回上级菜单......");
getch();
}
}
if(flag==0)
{
printf("\t对不起,你请求显示的学生信息不存在,请核实后重试!\n");
printf("\t按任意键继续......");
getch();
}
}while(flag==0);
return 0;
}
int show_class() //显示整个班级学生信息函数
{
if(j==0)
{
system("cls");
printf("\n\n\n\n\n\n\n\n\n\n\t\t 系统无任何可以显示的记录,请先行输入数据!");
printf("\n\n\t\t\t 按任意键返回......");
getch();
return 0;
}
char a[20];
int z;
int x;
int flag=0;
do
{
system("cls");
printf("\n\t需要显示的班级号码:");
scanf("%s",a);
for(z=0;z<j;z++)
{
if(strcmp(stu[z].classid,a)==0)
{
flag=1;
system("cls");
printf("\t%s %s 基本信息\n",stu[z].specialty,stu[z].classid);
for(x=0;x<j;x++)
{
if(strcmp(stu[x].classid,a)==0)
{
printf("\n\n\t姓名:%s",stu[z].name);
printf("\n\t性别:%s",stu[z].sex);
printf("\n\t身份证号:%s",stu[z].idcard);
printf("\n\t学院:%s",stu[z].academe);
printf("\n\t专业:%s",stu[z].specialty);
printf("\n\t班级:%s",stu[z].classid);
printf("\n\t学号:%s",stu[z].stuid);
printf("\n\t生源地:%s",stu[z].home);
}
}
printf("\n\n\t按任意键返回上级菜单......");
getch();
}
}
if(flag==0)
{
printf("\t对不起,你请求显示的班级信息不存在,请核实后重试!\n");
printf("\t按任意键继续......");
getch();
}
}while(flag==0);
return 0;
}

⑷ C语言库函数源代码

http://www.gnu.org/software/libc/这里就有所有的c标准库函数源码。

⑸ C语言库函数源代码在哪里有看

有安装vs2008或2010吗,在安装目录下面的VC/src中自带有源代码。比如我的就在
D:\Program Files\Microsoft Visual Studio 10.0\VC\crt\src中。没有的话发给你

⑹ 在哪里可以找到C语言标准库的实现源代码

Linux下的glic库的源码链接:
http://ftp.gnu.org/gnu/glibc/,你可以下载最新版本的glibc-2.24.tar.gz这个压缩文件,在Windows系统下直接用WinRAR解压即可,如果在Linux系统下用命令行解压的话,命令如下:tar -xzvf glibc-2.24.tar.gz。

⑺ c库函数源码

不是你表达不清,也许只是你根本不想仔细看一睛VC下面目录的源码,事实上就是有的。后附其中的qsort.c,以证明所言不虚。

VC的库是提供源码的,这东西也不值钱。
X:\Program Files\Microsoft Visual Studio\VCXX\CRT\SRC
注意有些可能本身是用汇编写的。

/***
*qsort.c - quicksort algorithm; qsort() library function for sorting arrays
*
* Copyright (c) 1985-1997, Microsoft Corporation. All rights reserved.
*
*Purpose:
* To implement the qsort() routine for sorting arrays.
*
*******************************************************************************/

#include <cruntime.h>
#include <stdlib.h>
#include <search.h>

/* prototypes for local routines */
static void __cdecl shortsort(char *lo, char *hi, unsigned width,
int (__cdecl *comp)(const void *, const void *));
static void __cdecl swap(char *p, char *q, unsigned int width);

/* this parameter defines the cutoff between using quick sort and
insertion sort for arrays; arrays with lengths shorter or equal to the
below value use insertion sort */

#define CUTOFF 8 /* testing shows that this is good value */

/***
*qsort(base, num, wid, comp) - quicksort function for sorting arrays
*
*Purpose:
* quicksort the array of elements
* side effects: sorts in place
*
*Entry:
* char *base = pointer to base of array
* unsigned num = number of elements in the array
* unsigned width = width in bytes of each array element
* int (*comp)() = pointer to function returning analog of strcmp for
* strings, but supplied by user for comparing the array elements.
* it accepts 2 pointers to elements and returns neg if 1<2, 0 if
* 1=2, pos if 1>2.
*
*Exit:
* returns void
*
*Exceptions:
*
*******************************************************************************/

/* sort the array between lo and hi (inclusive) */

void __cdecl qsort (
void *base,
unsigned num,
unsigned width,
int (__cdecl *comp)(const void *, const void *)
)
{
char *lo, *hi; /* ends of sub-array currently sorting */
char *mid; /* points to middle of subarray */
char *loguy, *higuy; /* traveling pointers for partition step */
unsigned size; /* size of the sub-array */
char *lostk[30], *histk[30];
int stkptr; /* stack for saving sub-array to be processed */

/* Note: the number of stack entries required is no more than
1 + log2(size), so 30 is sufficient for any array */

if (num < 2 || width == 0)
return; /* nothing to do */

stkptr = 0; /* initialize stack */

lo = base;
hi = (char *)base + width * (num-1); /* initialize limits */

/* this entry point is for pseudo-recursion calling: setting
lo and hi and jumping to here is like recursion, but stkptr is
prserved, locals aren't, so we preserve stuff on the stack */
recurse:

size = (hi - lo) / width + 1; /* number of el's to sort */

/* below a certain size, it is faster to use a O(n^2) sorting method */
if (size <= CUTOFF) {
shortsort(lo, hi, width, comp);
}
else {
/* First we pick a partititioning element. The efficiency of the
algorithm demands that we find one that is approximately the
median of the values, but also that we select one fast. Using
the first one proces bad performace if the array is already
sorted, so we use the middle one, which would require a very
wierdly arranged array for worst case performance. Testing shows
that a median-of-three algorithm does not, in general, increase
performance. */

mid = lo + (size / 2) * width; /* find middle element */
swap(mid, lo, width); /* swap it to beginning of array */

/* We now wish to partition the array into three pieces, one
consisiting of elements <= partition element, one of elements
equal to the parition element, and one of element >= to it. This
is done below; comments indicate conditions established at every
step. */

loguy = lo;
higuy = hi + width;

/* Note that higuy decreases and loguy increases on every iteration,
so loop must terminate. */
for (;;) {
/* lo <= loguy < hi, lo < higuy <= hi + 1,
A[i] <= A[lo] for lo <= i <= loguy,
A[i] >= A[lo] for higuy <= i <= hi */

do {
loguy += width;
} while (loguy <= hi && comp(loguy, lo) <= 0);

/* lo < loguy <= hi+1, A[i] <= A[lo] for lo <= i < loguy,
either loguy > hi or A[loguy] > A[lo] */

do {
higuy -= width;
} while (higuy > lo && comp(higuy, lo) >= 0);

/* lo-1 <= higuy <= hi, A[i] >= A[lo] for higuy < i <= hi,
either higuy <= lo or A[higuy] < A[lo] */

if (higuy < loguy)
break;

/* if loguy > hi or higuy <= lo, then we would have exited, so
A[loguy] > A[lo], A[higuy] < A[lo],
loguy < hi, highy > lo */

swap(loguy, higuy, width);

/* A[loguy] < A[lo], A[higuy] > A[lo]; so condition at top
of loop is re-established */
}

/* A[i] >= A[lo] for higuy < i <= hi,
A[i] <= A[lo] for lo <= i < loguy,
higuy < loguy, lo <= higuy <= hi
implying:
A[i] >= A[lo] for loguy <= i <= hi,
A[i] <= A[lo] for lo <= i <= higuy,
A[i] = A[lo] for higuy < i < loguy */

swap(lo, higuy, width); /* put partition element in place */

/* OK, now we have the following:
A[i] >= A[higuy] for loguy <= i <= hi,
A[i] <= A[higuy] for lo <= i < higuy
A[i] = A[lo] for higuy <= i < loguy */

/* We've finished the partition, now we want to sort the subarrays
[lo, higuy-1] and [loguy, hi].
We do the smaller one first to minimize stack usage.
We only sort arrays of length 2 or more.*/

if ( higuy - 1 - lo >= hi - loguy ) {
if (lo + width < higuy) {
lostk[stkptr] = lo;
histk[stkptr] = higuy - width;
++stkptr;
} /* save big recursion for later */

if (loguy < hi) {
lo = loguy;
goto recurse; /* do small recursion */
}
}
else {
if (loguy < hi) {
lostk[stkptr] = loguy;
histk[stkptr] = hi;
++stkptr; /* save big recursion for later */
}

if (lo + width < higuy) {
hi = higuy - width;
goto recurse; /* do small recursion */
}
}
}

/* We have sorted the array, except for any pending sorts on the stack.
Check if there are any, and do them. */

--stkptr;
if (stkptr >= 0) {
lo = lostk[stkptr];
hi = histk[stkptr];
goto recurse; /* pop subarray from stack */
}
else
return; /* all subarrays done */
}

/***
*shortsort(hi, lo, width, comp) - insertion sort for sorting short arrays
*
*Purpose:
* sorts the sub-array of elements between lo and hi (inclusive)
* side effects: sorts in place
* assumes that lo < hi
*
*Entry:
* char *lo = pointer to low element to sort
* char *hi = pointer to high element to sort
* unsigned width = width in bytes of each array element
* int (*comp)() = pointer to function returning analog of strcmp for
* strings, but supplied by user for comparing the array elements.
* it accepts 2 pointers to elements and returns neg if 1<2, 0 if
* 1=2, pos if 1>2.
*
*Exit:
* returns void
*
*Exceptions:
*
*******************************************************************************/

static void __cdecl shortsort (
char *lo,
char *hi,
unsigned width,
int (__cdecl *comp)(const void *, const void *)
)
{
char *p, *max;

/* Note: in assertions below, i and j are alway inside original bound of
array to sort. */

while (hi > lo) {
/* A[i] <= A[j] for i <= j, j > hi */
max = lo;
for (p = lo+width; p <= hi; p += width) {
/* A[i] <= A[max] for lo <= i < p */
if (comp(p, max) > 0) {
max = p;
}
/* A[i] <= A[max] for lo <= i <= p */
}

/* A[i] <= A[max] for lo <= i <= hi */

swap(max, hi, width);

/* A[i] <= A[hi] for i <= hi, so A[i] <= A[j] for i <= j, j >= hi */

hi -= width;

/* A[i] <= A[j] for i <= j, j > hi, loop top condition established */
}
/* A[i] <= A[j] for i <= j, j > lo, which implies A[i] <= A[j] for i < j,
so array is sorted */
}

/***
*swap(a, b, width) - swap two elements
*
*Purpose:
* swaps the two array elements of size width
*
*Entry:
* char *a, *b = pointer to two elements to swap
* unsigned width = width in bytes of each array element
*
*Exit:
* returns void
*
*Exceptions:
*
*******************************************************************************/

static void __cdecl swap (
char *a,
char *b,
unsigned width
)
{
char tmp;

if ( a != b )
/* Do the swap one character at a time to avoid potential alignment
problems. */
while ( width-- ) {
tmp = *a;
*a++ = *b;
*b++ = tmp;
}
}

⑻ 如何看c语言标准库函数的源代码

1、首先标准只是规定了这些函数的接口和具体的运行效率的要求,这些函数具体是怎么写得要看各个编译器的实现和平台。

2、例如使用的编译器是visual studio,微软提供了一部分C运行时(CRT)的源码,里面会有memcpy,strcpy之类的函数的实现,在visual studio 2005下的路径是C:Program FilesMicrosoft Visual Studio 8VCcrtsrc。

⑼ 谁能提供C语言stdio库函数源代码

http://mirrors.kernel.org/gnu/glibc/glibc-2.7.tar.gz
下载Linux的C语言标准库,它包含stdio.h等等

⑽ 如何查看C语言,内库的源代码

1、首先标准只是规定了这些函数的接口和具体的运行效率的要求,这些函数具体是怎么写得要看各个编译器的实现和平台。
2、例如使用的编译器是visual studio,微软提供了一部分C运行时(CRT)的源码,里面会有memcpy,strcpy之类的函数的实现,在visual studio 2005下的路径是C:\Program Files\Microsoft Visual Studio 8\VC\crt\src。

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