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js颜色算法

发布时间:2022-12-22 23:04:54

❶ 求js中颜色值变浅的算法,类似于下图

首先你的了解颜色的概念

下面我简单介绍下颜色概念在32位系统上我们所看到的颜色由RGB三原色显示再加上一个透明度通道就形成了多种多样的颜色

多的我就不多说了下面直接写一份演示代码

<!DOCTYPEhtml>
<html>
<head>
<title>test</title>
<style>
.tsetDiv{
width:40px;
height:40px;
border-radius:100%;
font-size:0;
display:inline-block;
margin-left:10px;
vertical-align:middle;
}
#boxF{
width:300px;
font-size:0;
height:auto;
}
</style>
</head>
<body>
<divid="boxF"></div>
<scripttype="text/javascript">
varboxf=document.getElementById("boxF");
vardivC=null;
varr=0;
varg=0;
varb=0;
for(vari=0;i<10;i++){
for(varj=0;j<10;j++){
divC=document.createElement("div");
divC.style.backgroundColor="rgb("+r+","+g+","+b+")";

divC.setAttribute("class","tsetDiv");
boxf.appendChild(divC);
}
//修改rgb加的不同值可以得到不同的效果rgb最大值为255所以不用担心超过不显示
r+=15;
g+=25;
b+=35;
}
</script>
</body>
</html>

运行效果为下图

❷ JavaScript如何计算两个颜色之间的渐变色值

❸ 求js颜色转换算法

(function(d){function h(a,b,e){var c="rgb"+(d.support.rgba?"a":"")+"("+parseInt(a[0]+e*(b[0]-a[0]),10)+","+parseInt(a[1]+e*(b[1]-a[1]),10)+","+parseInt(a[2]+e*(b[2]-a[2]),10);d.support.rgba&&(c+=","+(a&&b?parseFloat(a[3]+e*(b[3]-a[3])):1));return c+")"}function f(a){var b;return(b=/#([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})/.exec(a))?[parseInt(b[1],16),parseInt(b[2],16),parseInt(b[3],16),1]:(b=/#([0-9a-fA-F])([0-9a-fA-F])([0-9a-fA-F])/.exec(a))?[17*parseInt(b[1],16),17*parseInt(b[2],
16),17*parseInt(b[3],16),1]:(b=/rgb\(\s*([0-9]{1,3})\s*,\s*([0-9]{1,3})\s*,\s*([0-9]{1,3})\s*\)/.exec(a))?[parseInt(b[1]),parseInt(b[2]),parseInt(b[3]),1]:(b=/rgba\(\s*([0-9]{1,3})\s*,\s*([0-9]{1,3})\s*,\s*([0-9]{1,3})\s*,\s*([0-9\.]*)\s*\)/.exec(a))?[parseInt(b[1],10),parseInt(b[2],10),parseInt(b[3],10),parseFloat(b[4])]:l[a]}d.extend(!0,d,{support:{rgba:function(){var a=d("script:first"),b=a.css("color"),e=!1;if(/^rgba/.test(b))e=!0;else try{e=b!=a.css("color","rgba(0, 0, 0, 0.5)").css("color"),
a.css("color",b)}catch(c){}return e}()}});var k="color backgroundColor borderBottomColor borderLeftColor borderRightColor borderTopColor outlineColor".split(" ");d.each(k,function(a,b){d.Tween.propHooks[b]={get:function(a){return d(a.elem).css(b)},set:function(a){var c=a.elem.style,g=f(d(a.elem).css(b)),m=f(a.end);a.run=function(a){c[b]=h(g,m,a)}}}});d.Tween.propHooks.borderColor={set:function(a){var b=a.elem.style,e=[],c=k.slice(2,6);d.each(c,function(b,c){e[c]=f(d(a.elem).css(c))});var g=f(a.end);
a.run=function(a){d.each(c,function(d,c){b[c]=h(e[c],g,a)})}}};var l={aqua:[0,255,255,1],azure:[240,255,255,1],beige:[245,245,220,1],black:[0,0,0,1],blue:[0,0,255,1],brown:[165,42,42,1],cyan:[0,255,255,1],darkblue:[0,0,139,1],darkcyan:[0,139,139,1],darkgrey:[169,169,169,1],darkgreen:[0,100,0,1],darkkhaki:[189,183,107,1],darkmagenta:[139,0,139,1],darkolivegreen:[85,107,47,1],darkorange:[255,140,0,1],darkorchid:[153,50,204,1],darkred:[139,0,0,1],darksalmon:[233,150,122,1],darkviolet:[148,0,211,1],fuchsia:[255,
0,255,1],gold:[255,215,0,1],green:[0,128,0,1],indigo:[75,0,130,1],khaki:[240,230,140,1],lightblue:[173,216,230,1],lightcyan:[224,255,255,1],lightgreen:[144,238,144,1],lightgrey:[211,211,211,1],lightpink:[255,182,193,1],lightyellow:[255,255,224,1],lime:[0,255,0,1],magenta:[255,0,255,1],maroon:[128,0,0,1],navy:[0,0,128,1],olive:[128,128,0,1],orange:[255,165,0,1],pink:[255,192,203,1],purple:[128,0,128,1],violet:[128,0,128,1],red:[255,0,0,1],silver:[192,192,192,1],white:[255,255,255,1],yellow:[255,255,
0,1],transparent:[255,255,255,0]}})(jQuery);

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