话不多说，直接上菜
为了方便大家，我就不分段解释了
import turtle, random
# 定义一个类，用来画除了数字方块之外的图形
class BackGround(turtle.Turtle):
def __init__(self):
super().__init__()
self.penup()
self.ht()
def draw_block(self):
self.shape('bg.gif') # 画出背景方块
改则猜 for i in allpos:
self.goto(i)
self.stamp()
self.color('white', 'white') # 画出其他背景
self.goto(-215, 120)
self.begin_fill()
self.goto(215, 120)
self.goto(215, 110)
self.goto(-215, 110)
self.end_fill()
self.shape('title.gif')
self.goto(-125, 210)
self.stamp()
self.shape('score.gif')
self.goto(125, 245)
self.stamp()
self.shape('top_score.gif')
self.goto(125, 170)
self.stamp()
# 游戏失败及达成2048的提示文字
def judge(self):
global flag_win, flag_win_lose_text
self.color('blue')
judge = 0 # 判断是否还有位置可以移动
for i in block_dic.values():
for j in block_dic.values():
if i.num == 0 or i.num == j.num and i.distance(j) == 100:
judge += 1
if judge == 0: # 无位置可移动，游戏失败
self.write(' GAME OVER\n重新开始请按空格键', align='center', font=('黑体', 30, 'bold'))
盯数 flag_win_lose_text = False
if flag_win is True: # 此条件让2048达成的判断只能进行一次
for k in block_dic.values():
if k.num == 2048: # 游戏达成
核型 flag_win = False
self.write(' 达成2048\n继续游戏请按回车键', align='center', font=('黑体', 30, 'bold'))
flag_win_lose_text = False
def win_lose_clear(self):
global flag_win_lose_text
self.clear()
flag_win_lose_text = True
def show_score(self): # 分值的显示
global score, top_score
if score > top_score:
top_score = score
with open('.\\score.txt', 'w') as f:
f.write(f'{top_score}')
self.color('white')
self.goto(125, 210)
self.clear()
self.write(f'{score}', align='center', font=('Arial', 20, 'bold'))
self.goto(125, 135)
self.write(f'{top_score}', align='center', font=('Arial', 20, 'bold'))
# 数字方块类
class Block(turtle.Turtle):
def __init__(self):
super().__init__()
self.ht()
self.penup()
self.num = 0
def draw(self):
self.clear()
dic_draw = {2: '#eee6db', 4: '#efe0cd', 8: '#f5af7b',
16: '#fb9660', 32: '#f57d5a', 64: '#f95c3d',
128: '#eccc75', 256: '#eece61', 512: '#efc853',
1024: '#ebc53c', 2048: '#eec430', 4096: '#aeb879',
8192: '#aab767', 16384: '#a6b74f'}
if self.num > 0: # 数字大于0，画出方块
self.color(f'{dic_draw[self.num]}') # 选择颜色
self.begin_fill()
self.goto(self.xcor()+48, self.ycor()+48)
self.goto(self.xcor()-96, self.ycor())
self.goto(self.xcor(), self.ycor()-96)
self.goto(self.xcor()+96, self.ycor())
self.goto(self.xcor(), self.ycor()+96)
self.end_fill()
self.goto(self.xcor()-48, self.ycor()-68)
if self.num > 4: # 按照数字选择数字的颜色
self.color('white')
else:
self.color('#6d6058')
self.write(f'{self.num}', align='center', font=('Arial', 27, 'bold'))
self.goto(self.xcor(), self.ycor()+20)
class Game():
def init(self):
back = BackGround() # 实例画出游戏的背景
back.draw_block()
for i in allpos: # 画出16个海龟对应16个数字块
block = Block()
block.goto(i)
block_dic[i] = block
game.grow()
def restart(self): # 重开游戏的方法
global score, flag_win_lose_text
score = 0
for i in block_dic.values():
i.num = 0
i.clear()
win_lose_text.clear()
game.grow()
flag_win_lose_text = True # 此flag为游戏达成或失败出现提示语后的判断，要提示语被clear后才能继续move
def grow(self): # 随机出现一个2或4的数字块
block_list = []
for i in allpos:
if block_dic[i].num == 0:
block_list.append(block_dic[i]) # 挑出空白方块的海龟
turtle_choice = random.choice(block_list) # 随机选中其中一个海龟
turtle_choice.num = random.choice([2, 2, 2, 2, 4]) # 赋属性num=2/4
turtle_choice.draw()
win_lose_text.judge()
show_score_text.show_score()
ms.update()
def move_up(self):
allpos1 = allpos[::4] # 切片为四列
allpos2 = allpos[1::4]
allpos3 = allpos[2::4]
allpos4 = allpos[3::4]
self.move_move(allpos1, allpos2, allpos3, allpos4)
def move_down(self):
allpos1 = allpos[-4::-4]
allpos2 = allpos[-3::-4]
allpos3 = allpos[-2::-4]
allpos4 = allpos[-1::-4]
self.move_move(allpos1, allpos2, allpos3, allpos4)
def move_left(self):
allpos1 = allpos[:4]
allpos2 = allpos[4:8]
allpos3 = allpos[8:12]
allpos4 = allpos[12:16]
self.move_move(allpos1, allpos2, allpos3, allpos4)
def move_right(self):
allpos1 = allpos[-1:-5:-1]
allpos2 = allpos[-5:-9:-1]
allpos3 = allpos[-9:-13:-1]
allpos4 = allpos[-13:-17:-1]
self.move_move(allpos1, allpos2, allpos3, allpos4)
def move_move(self, allpos1, allpos2, allpos3, allpos4):
if flag_win_lose_text is True:
count1 = self.move(allpos1) # 四列或四行依次移动
count2 = self.move(allpos2)
count3 = self.move(allpos3)
count4 = self.move(allpos4)
if count1 or count2 or count3 or count4: # 判断是否有方块移动，有才能继续出现新的数字块
self.grow()
def move(self, pos_list):
num_list = [] # 为某一列或行的数字块海龟的坐标
for i in pos_list:
num_list.append(block_dic[i].num) # 把这些海龟的NUM形成list
new_num_list, count = self.list_oper(num_list) # 只是list_oper的方法形成新的list
for j in range(len(new_num_list)): # 把新的list依次赋值给对应的海龟.num属性并调用draw()方法
block_dic[pos_list[j]].num = new_num_list[j]
block_dic[pos_list[j]].draw()
return count
def list_oper(self, num_list): # num_list的操作，假设其为【2,0,2,2】
global score
count = True
temp = []
new_temp = []
for j in num_list:
if j != 0:
temp.append(j) # temp=[2,2,2]
flag = True
for k in range(len(temp)):
if flag:
if k < len(temp)-1 and temp[k] == temp[k+1]:
new_temp.append(temp[k]*2)
flag = False
score += temp[k]
else:
new_temp.append(temp[k]) # new_temp=[4,2]
else:
flag = True
for m in range(len(num_list)-len(new_temp)):
new_temp.append(0) # new_temp=[4,2,0,0]
if new_temp == num_list:
count = False # 此变量判断num_list没有变化，数字块无移动
return(new_temp, count)
if __name__ == '__main__':
ms = turtle.Screen() # 主窗口的设置
ms.setup(430, 630, 400, 50)
ms.bgcolor('gray')
ms.title('2048')
ms.tracer(0)
ms.register_shape('bg.gif')
ms.register_shape('title.gif')
ms.register_shape('score.gif')
ms.register_shape('top_score.gif')
block_dic = {} # 放数字方块海龟的字典，位置坐标为key,对应海龟为value
allpos = [(-150, 50), (-50, 50), (50, 50), (150, 50),
(-150, -50), (-50, -50), (50, -50), (150, -50),
(-150, -150), (-50, -150), (50, -150), (150, -150),
(-150, -250), (-50, -250), (50, -250), (150, -250)]
flag_win = True # 达成2048的判断，让达成的文字仅出现一次
flag_win_lose_text = True # 用来判断失败或成功的提示文字是否有被清除，不清除不能继续移动方块
score = 0
with open('.\\score.txt', 'r') as f:
top_score = int(f.read()) # 读取score中的数据
show_score_text = BackGround()
win_lose_text = BackGround()
game = Game()
game.init()
ms.listen()
ms.onkey(game.move_up, 'Up')
ms.onkey(game.move_down, 'Down')
ms.onkey(game.move_left, 'Left')
ms.onkey(game.move_right, 'Right')
ms.onkey(win_lose_text.win_lose_clear, 'Return')
ms.onkey(game.restart, 'space')
ms.mainloop()
这是游戏界面：
欢迎挑战最高分。
要运行出来，必须本地要有这些文件：bg.gif，score.gif，title.gif，top_score.gif，score.txt
我把这些文件放在了群里，还有一些学习的资料，群号642109462，欢迎对python感兴趣的进群讨论。
支持作者的，可以关注和点赞。感谢你们！
❷ 如何实现用javascript实现rsa加解密
用javascript实现rsa加解密的实现方式是通过PKCS完成的。
1、整个定义的function
function pkcs1pad2(s,n) {
if(n < s.length + 11) { // TODO: fix for utf-8
alert("Message too long for RSA");
return null;
}
var ba = new Array();
var i = s.length - 1;
while(i >= 0 && n > 0) {
var c = s.charCodeAt(i--);
//UTF-8编码为变长字节,使用实际的字节来记录
if(c < 128) { // encode using utf-8
ba[--n] = c;
}
else if((c > 127) && (c < 2048)) {
ba[--n] = (c & 63) | 128;
ba[--n] = (c >> 6) | 192;
}
else {
ba[--n] = (c & 63) | 128;
ba[--n] = ((c >> 6) & 63) | 128;
ba[--n] = (c >> 12) | 224;
}
}
//实际输入拼装结束,将下一位赋值为0标记结束
ba[--n] = 0;
var rng = new SecureRandom();
var x = new Array();
//拼接随机非0字节
while(n > 2) { // random non-zero pad
x[0] = 0;
while(x[0] == 0) rng.nextBytes(x);
ba[--n] = x[0];
}
//这两位做简单的校验
ba[--n] = 2;
ba[--n] = 0;
return new BigInteger(ba);
}
该方法中对UTF-8字符进行了兼容，并且在拼装完实际输入的字符后，还拼装了随机的字节，使用拼装后的字符串去加密。由于每次拼装的结果是随机的，这样每次加密后的密文都不同。
2、调用方法：；
function RSAEncrypt(text) {
var m = pkcs1pad2(text,(this.n.bitLength()+7)>>3);
if(m == null) return null;
var c = this.doPublic(m);
if(c == null) return null;
var h = c.toString(16);
if((h.length & 1) == 0) return h; else return "0" + h;
}
❸ 如何通过js HTML5上传示例代码
HTML5版本，只要支持HTML5的浏览器都可以正常使用，并对触摸屏（手机，平板）进行了优化
IE9+ Firefox Chrome Opera
Safari IPhone4 iPad2 Android 2.1CFUpdate HTML5版本，只要支持HTML5的浏览器都可以正常使用，并对触摸屏（手机，平板）进行了优化
IE9+ Firefox
Chrome Opera Safari IPhone4 iPad2 Android 2.1
❹ 如何实现用javascript实现rsa加解密
服务端生成公钥与私钥，保存。
客户端在请求到登录页面后，随机生成一字符串。
后此随机字符串作为密钥加密密码，再用从服务端获取到的公钥加密生成的随机字符串
将此两段密文传入服务端，服务端用私钥解出随机字符串，再用此私钥解出加密的密文。这其中有一个关键是解决服务端的公钥，传入客户端，客户端用此公钥加密字符串后，后又能在服务端用私钥解出。
步骤：
服务端的RSAJava实现：
/**
*
*/
packagecom.sunsoft.struts.util;
importjava.io.ByteArrayOutputStream;
importjava.io.FileInputStream;
importjava.io.FileOutputStream;
importjava.io.ObjectInputStream;
importjava.io.ObjectOutputStream;
importjava.math.BigInteger;
importjava.security.KeyFactory;
importjava.security.KeyPair;
importjava.security.KeyPairGenerator;
importjava.security.NoSuchAlgorithmException;
importjava.security.PrivateKey;
importjava.security.PublicKey;
importjava.security.SecureRandom;
importjava.security.interfaces.RSAPrivateKey;
importjava.security.interfaces.RSAPublicKey;
importjava.security.spec.InvalidKeySpecException;
importjava.security.spec.RSAPrivateKeySpec;
importjava.security.spec.RSAPublicKeySpec;
importjavax.crypto.Cipher;/**
*RSA工具类。提供加密，解密，生成密钥对等方法。
*需要到
下载bcprov-jdk14-123.jar。
*
*/
publicclassRSAUtil{
/**
**生成密钥对*
*
*@returnKeyPair*
*@throwsEncryptException
*/
()throwsException{
try{
KeyPairGeneratorkeyPairGen=KeyPairGenerator.getInstance("RSA",
neworg.bouncycastle.jce.provider.BouncyCastleProvider());
finalintKEY_SIZE=1024;//没什么好说的了，这个值关系到块加密的大小，可以更改，但是不要太大，否则效率会低
keyPairGen.initialize(KEY_SIZE,newSecureRandom());
KeyPairkeyPair=keyPairGen.generateKeyPair();
saveKeyPair(keyPair);
returnkeyPair;
}catch(Exceptione){
thrownewException(e.getMessage());
}
}
publicstaticKeyPairgetKeyPair()throwsException{
FileInputStreamfis=newFileInputStream("C:/RSAKey.txt");
ObjectInputStreamoos=newObjectInputStream(fis);
KeyPairkp=(KeyPair)oos.readObject();
oos.close();
fis.close();
returnkp;
}
publicstaticvoidsaveKeyPair(KeyPairkp)throwsException{
FileOutputStreamfos=newFileOutputStream("C:/RSAKey.txt");
ObjectOutputStreamoos=newObjectOutputStream(fos);
//生成密钥
oos.writeObject(kp);
oos.close();
fos.close();
}
/**
**生成公钥*
*
*@parammolus*
*@parampublicExponent*
*@returnRSAPublicKey*
*@throwsException
*/
(byte[]molus,
byte[]publicExponent)throwsException{
KeyFactorykeyFac=null;
try{
keyFac=KeyFactory.getInstance("RSA",
neworg.bouncycastle.jce.provider.BouncyCastleProvider());
}catch(NoSuchAlgorithmExceptionex){
thrownewException(ex.getMessage());
}
RSAPublicKeySpecpubKeySpec=newRSAPublicKeySpec(newBigInteger(
molus),newBigInteger(publicExponent));
try{
return(RSAPublicKey)keyFac.generatePublic(pubKeySpec);
}catch(InvalidKeySpecExceptionex){
thrownewException(ex.getMessage());
}
}
/**
**生成私钥*
*
*@parammolus*
*@paramprivateExponent*
*@returnRSAPrivateKey*
*@throwsException
*/
(byte[]molus,
byte[]privateExponent)throwsException{
KeyFactorykeyFac=null;
try{
keyFac=KeyFactory.getInstance("RSA",
neworg.bouncycastle.jce.provider.BouncyCastleProvider());
}catch(NoSuchAlgorithmExceptionex){
thrownewException(ex.getMessage());
}
RSAPrivateKeySpecpriKeySpec=newRSAPrivateKeySpec(newBigInteger(
molus),newBigInteger(privateExponent));
try{
return(RSAPrivateKey)keyFac.generatePrivate(priKeySpec);
}catch(InvalidKeySpecExceptionex){
thrownewException(ex.getMessage());
}
}
/**
**加密*
*
*@paramkey
*加密的密钥*
*@paramdata
*待加密的明文数据*
*@return加密后的数据*
*@throwsException
*/
publicstaticbyte[]encrypt(PublicKeypk,byte[]data)throwsException{
try{
Ciphercipher=Cipher.getInstance("RSA",
neworg.bouncycastle.jce.provider.BouncyCastleProvider());
cipher.init(Cipher.ENCRYPT_MODE,pk);
intblockSize=cipher.getBlockSize();//获得加密块大小，如：加密前数据为128个byte，而key_size=1024
//加密块大小为127
//byte,加密后为128个byte;因此共有2个加密块，第一个127
//byte第二个为1个byte
intoutputSize=cipher.getOutputSize(data.length);//获得加密块加密后块大小
intleavedSize=data.length%blockSize;
intblocksSize=leavedSize!=0?data.length/blockSize+1
:data.length/blockSize;
byte[]raw=newbyte[outputSize*blocksSize];
inti=0;
while(data.length-i*blockSize>0){
if(data.length-i*blockSize>blockSize)
cipher.doFinal(data,i*blockSize,blockSize,raw,i
*outputSize);
else
cipher.doFinal(data,i*blockSize,data.length-i
*blockSize,raw,i*outputSize);
//这里面doUpdate方法不可用，查看源代码后发现每次doUpdate后并没有什么实际动作除了把byte[]放到
//ByteArrayOutputStream中，而最后doFinal的时候才将所有的byte[]进行加密，可是到了此时加密块大小很可能已经超出了
//OutputSize所以只好用dofinal方法。
i++;
}
returnraw;
}catch(Exceptione){
thrownewException(e.getMessage());
}
}
/**
**解密*
*
*@paramkey
*解密的密钥*
*@paramraw
*已经加密的数据*
*@return解密后的明文*
*@throwsException
*/
publicstaticbyte[]decrypt(PrivateKeypk,byte[]raw)throwsException{
try{
Ciphercipher=Cipher.getInstance("RSA",
neworg.bouncycastle.jce.provider.BouncyCastleProvider());
cipher.init(cipher.DECRYPT_MODE,pk);
intblockSize=cipher.getBlockSize();
ByteArrayOutputStreambout=newByteArrayOutputStream(64);
intj=0;
while(raw.length-j*blockSize>0){
bout.write(cipher.doFinal(raw,j*blockSize,blockSize));
j++;
}
returnbout.toByteArray();
}catch(Exceptione){
thrownewException(e.getMessage());
}
}
/**
***
*
*@paramargs*
*@throwsException
*/
publicstaticvoidmain(String[]args)throwsException{
RSAPublicKeyrsap=(RSAPublicKey)RSAUtil.generateKeyPair().getPublic();
Stringtest="helloworld";
byte[]en_test=encrypt(getKeyPair().getPublic(),test.getBytes());
byte[]de_test=decrypt(getKeyPair().getPrivate(),en_test);
System.out.println(newString(de_test));
}
}
测试页面IndexAction.java：
/*
*GeneratedbyMyEclipseStruts
*Templatepath:templates/java/JavaClass.vtl
*/
packagecom.sunsoft.struts.action;
importjava.security.interfaces.RSAPrivateKey;
importjava.security.interfaces.RSAPublicKey;
importjavax.servlet.http.HttpServletRequest;
importjavax.servlet.http.HttpServletResponse;
importorg.apache.struts.action.Action;
importorg.apache.struts.action.ActionForm;
importorg.apache.struts.action.ActionForward;
importorg.apache.struts.action.ActionMapping;
importcom.sunsoft.struts.util.RSAUtil;
/**
*MyEclipseStruts
*Creationdate:06-28-2008
*
*XDocletdefinition:
*@struts.actionvalidate="true"
*/
{
/*
*GeneratedMethods
*/
/**
*Methodexecute
*@parammapping
*@paramform
*@paramrequest
*@paramresponse
*@returnActionForward
*/
publicActionForwardexecute(ActionMappingmapping,ActionFormform,
HttpServletRequestrequest,HttpServletResponseresponse)throwsException{
RSAPublicKeyrsap=(RSAPublicKey)RSAUtil.getKeyPair().getPublic();
Stringmole=rsap.getMolus().toString(16);
Stringempoent=rsap.getPublicExponent().toString(16);
System.out.println("mole");
System.out.println(mole);
System.out.println("empoent");
System.out.println(empoent);
request.setAttribute("m",mole);
request.setAttribute("e",empoent);
returnmapping.findForward("login");
}
}
通过此action进入登录页面，并传入公钥的Molus 与PublicExponent的hex编码形式。