phpjson字符串解析

A. php解析不了JSON

• $keys = '{result:0,events:[{event:6}]}'; $string = json_decode($key...

• 答：json_decode( ) 可以实现对JSON格式的字符串进行编码 你的Json字符串有问题 结果：array(2) { ["result"] => int(0) ["events"] => array(1) { [0] => array(1) { ["event"] => int(6) } }}

B. PHP 如何解析JOSN格式字符串 转换为数组

$str = " {"personMsg":{"phone":"11","birth":"2010-07-14","headImg":"11","email":"11","personId":1,"gender":0,"personName":"闄堥"},"friendIdList":["2","10"],"sessionKey":"Oh0aXV/fotUtdV1gTMqI5w==","code":"200","operateData":[{"operate":"1","friendId":"2","version":"3"},{"operate":"2","friendId":"39","version":"4"},{"operate":"1","friendId":"1","version":"21212"},{"operate":"2","friendId":"100","version":"6"},{"operate":"2","friendId":"38","version":"7"},{"operate":"2","friendId":"40","version":"8"},{"operate":"2","friendId":"56","version":"9"},{"operate":"2","friendId":"96","version":"10"},{"operate":"2","friendId":"93","version":"11"},{"operate":"1","friendId":"100","version":"21213"},{"operate":"1","friendId":"39","version":"21214"},{"operate":"1","friendId":"93","version":"21215"},{"operate":"1","friendId":"96","version":"21216"},{"operate":"1","friendId":"10","version":"21217"},{"operate":"1","friendId":"38","version":"21218"},{"operate":"1","friendId":"40","version":"21219"},{"operate":"1","friendId":"40","version":"21220"},{"operate":"1","friendId":"40","version":"21221"},{"operate":"1","friendId":"56","version":"21222"}]}";

var_Export(json_decode($str, 1)); // json_decode 必须指定第二个参数，不然会返回一个对象，而不是数组～

C. 问大佬php中如何用 foreach解析json

首先，不推荐使用foreach进行自己去解析json字符串，因为php已经封装了非常好用，且效率不低的内置方法，这个方法就是json_decode。
使用这个函数，可以直接把json数据转换成数据或者对象，这个是可以控制的。转换成对象或者数组之后，再使用foreach就可以方便遍历得到想要的数据。

D. php解析json并输出到html页面

用json_decode()将json字符串转化成php数组，然后直接循环数组取出值即可。
<?php
$content= file_get_contents('获取json字符串的url');
$content = json_decode($content);//将json字符串转化成php数组
foreach ($content as $key ) {//循环数组
echo '<li>' . $key['city'] . '</li>';
echo '<li>' . $key['city_en'] . '</li>';
echo '<li>' . $key['date_y'] . '</li>';
echo '<li>' . $key['week'] . '</li>';
}

E. 请问PHP如何解析这样的json值如何获取其中某个值内容呢 代码如下:

PHP里面有对函数 是转换JSON为字符串 和JSON转化为字符串的函数，你定义一个变量=解析（JSON字符串）然后打印一下 取对应的键名就可以得到想要的内容了

F. PHP怎么解析json数据

//使用json_decode函数解码
$arr=json_decode($json,true);
$number=$arr['number'];

G. php如何解析这样的json字符串

$jsonStr = '{"msg":{"auth":"Yes_auth","ddid":"1","payje":0.3,"payzt":"SUCCESS"}}'; $arr = json_decode($jsonStr, true); $payzt = $arr['msg']['payzt']; // 或者 $jsonStr = '{"msg":{"auth":"Yes_auth","ddid":"1","payje":0.3,"payzt":"SUCCESS"}}'; $arr = json_decode($jsonStr); $payzt = $arr->msg->payzt;

关键是对json_decode函数的使用。

H. php解析json问题

$r = json_decode({"code":200,"result":[这里是json数据]｝);
$r->result 就是你的数据

I. PHP中这个字符串JSON格式吗应该怎么解析

php里没有json格式。。需要decode解析。。encode编码。另外我是猜的

J. php 解析json 字符串，真的没人会吗求大神解答

$a=['2'=>2,'3'=>3,'4'=>json_encode(['5'=>'5','6'=>'6'])];
$b=['a'=>json_encode($a),'b'=>['a'=>'b']];
$json_code=json_encode($b);

echo$json_code;
echo"

";
$json_str='{"a":"{"2":2,"3":3,"4":"{\"5\":\"5\",\"6\":\"6\"}"}","b":{"a":"b"}}';

//这两个并不相等
var_mp($json_code);
var_mp($json_str);

echo"

";
//这样才相等
$json_str='{"a":"{"2":2,"3":3,"4":"{\"5\":\"5\",\"6\":\"6\"}"}","b":{"a":"b"}}';
$json_str=str_replace("\\","\\\",$json_str);


echo"

";
echo$json_str;
echo"

";

$arr=json_decode($json_str,true);
print_r($arr);