① c语言 贪吃蛇 程序
基本思路:
蛇每吃一个食物蛇身子就增加一格,用UP, DOWN, LEFT, RIGHT控制蛇头的运动,而蛇身子跟着蛇头走,每后一格蛇身子下一步走到上一格蛇身子的位置,以此类推。
#include <stdio.h>
#include <conio.h>
#include <windows.h>
#define BEG_X 2
#define BEG_Y 1
#define WID 20
#define HEI 20
HANDLE hout;
typedef enum {UP, DOWN, LEFT, RIGHT} DIR;
typedef struct Snake_body
{
COORD pos;//蛇身的位置
struct Snake_body *next;//下一个蛇身
struct Snake_body *prev;//前一个蛇身
}SNAKE, *PSNAKE;
PSNAKE head = NULL;//蛇头
PSNAKE tail = NULL;//蛇尾
//画游戏边框的函数
void DrawBorder()
{
int i, j;
COORD pos = {BEG_X, BEG_Y};
for(i = 0; i < HEI; ++i)
{
SetConsoleCursorPosition(hout, pos);
for(j = 0; j < WID; ++j)
{
if(i == 0)//第一行
{
if(j == 0)
printf("┏");
else if(j == WID - 1)
printf("┓");
else
printf("━");
}
else if(i == HEI - 1)//最后一行
{
if(j == 0)
printf("┗");
else if(j == WID - 1)
printf("┛");
else
printf("━");
}
else if(j == 0 || j == WID - 1)//第一列或最后一列
printf("┃");
else
printf(" ");
}
++pos.Y;
}
}
//添加蛇身的函数
void AddBody(COORD pos)
{
PSNAKE pnew = (PSNAKE)calloc(1, sizeof(SNAKE));
pnew->pos = pos;
if(!head)
{
head = tail = pnew;
}
else
{
pnew->next = head;//新创建蛇身的next指向原先的蛇头
head->prev = pnew;//原先的蛇头的prev指向新创建的蛇身
head = pnew;//把新创建的蛇身作为新的蛇头
}
SetConsoleCursorPosition(hout, head->pos);
printf("◎");
}
//蛇身移动的函数
void MoveBody(DIR dir)
{
PSNAKE ptmp;
COORD pos = head->pos;
switch(dir)
{
case UP:
if(head->pos.Y > BEG_Y + 1)
--pos.Y;
else
return;
break;
case DOWN:
if(head->pos.Y < BEG_Y + HEI - 2)
++pos.Y;
else
return;
break;
case LEFT:
if(head->pos.X > BEG_X + 2)
pos.X -= 2;
else
return;
break;
case RIGHT:
if(head->pos.X < BEG_X + (WID - 2) * 2)
pos.X += 2;
else
return;
break;
}
AddBody(pos);//添加了一个新的蛇头
ptmp = tail;//保存当前的蛇尾
tail = tail->prev;
if(tail)
tail->next = NULL;
SetConsoleCursorPosition(hout, ptmp->pos);
printf(" ");
free(ptmp);
}
int main()
{
int ctrl;
DIR dir = RIGHT;//初始蛇的方向是向右的
COORD pos = {BEG_X + 2, BEG_Y + HEI / 2};
system("color 0E");
system("mode con cols=90 lines=30");
hout = GetStdHandle(STD_OUTPUT_HANDLE);
printf(" ------------贪吃蛇的移动------------");
DrawBorder();
//自定义几个蛇的身体
AddBody(pos);
pos.X += 2;
AddBody(pos);
pos.X += 2;
AddBody(pos);
pos.X += 2;
AddBody(pos);
pos.X += 2;
AddBody(pos);
pos.X += 2;
AddBody(pos);
pos.X += 2;
AddBody(pos);
//控制蛇的移动
while(ctrl = getch())
{
switch(ctrl)
{
case 'w':
if(dir == DOWN)
continue;
dir = UP;
break;
case 's':
if(dir == UP)
continue;
dir = DOWN;
break;
case 'a':
if(dir == RIGHT)
continue;
dir = LEFT;
break;
case 'd':
if(dir == LEFT)
continue;
dir = RIGHT;
break;
case 'q':
return 0;
}
MoveBody(dir);
}
return 0;
}
(1)贪吃蛇编程思路扩展阅读:
实现逻辑
1,可以设置光标,就能实现制定位置打印制定符号。
2,涉及一个结构体,包含两个元素坐标元素和一个结构体指针。
3,结构体串联形成链表,遍历获取成员坐标,打印符号得到蛇身。
4,不断的加头,去尾,重新遍历坐标,再打印形成蛇的移动。
5,食物产生的位置判定,不能越界,也不能与蛇身体重合。
6,蛇的转向判定,一条规则,不允许倒退。
7,转向的实现,跟行进方向决定新的关节坐标(当前头的上下左右)
8,死亡检测,是否头节点坐标是否与墙壁重合,是否与身体其他关节重合。
9,加速减速,设置刷新休眠时间实现。
② 贪吃蛇 C语言 简易程序设计
#include<graphics.h>
#include<stdlib.h>
#define N 200
#define up 0x4800
#define down 0x5000
#define left 0x4b00
#define right 0x4d00
#define esc 0x011b
#define Y 0x1579
#define n 0x316e
int gamespeed; /* 游戏速度 */
int i,key,color;
int score=0; /* 游戏分数 */
char cai48H[]={
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x04,0x00,0x18,0x00,0x00,0x00,0x0E,0x00,
0x1C,0x00,0x00,0x00,0x1C,0x00,0x1C,0x00,
0x00,0x00,0x20,0x00,0x38,0x00,0x00,0x00,
0x40,0x00,0x78,0x00,0x00,0x01,0x80,0x40,
0x70,0x00,0x00,0x03,0x80,0xC0,0xE0,0x00,
0x00,0x07,0x80,0x80,0xC0,0x00,0x00,0x0E,
0x11,0x81,0xC0,0x00,0x00,0x08,0x61,0x01,
0x80,0x00,0x00,0x00,0x23,0x03,0x04,0x00,
0x00,0x02,0x02,0x00,0x06,0x00,0x00,0x1E,
0x04,0x00,0x0F,0x00,0x00,0x1C,0x1F,0x80,
0x1E,0x00,0x00,0x08,0x3F,0x80,0x3C,0x00,
0x00,0x00,0xFF,0x80,0x38,0x00,0x00,0x03,
0xFF,0x80,0x78,0x00,0x00,0x0F,0xF8,0x00,
0xF0,0x00,0x00,0x7F,0xF0,0x00,0xE0,0x00,
0x03,0xFF,0xFC,0x01,0x80,0x00,0x03,0xC0,
0xFF,0x01,0x03,0x80,0x01,0x01,0xFF,0x00,
0x03,0x80,0x00,0x01,0x3F,0x00,0x07,0x80,
0x00,0x02,0x11,0x00,0x07,0x00,0x00,0x00,
0x10,0x00,0x07,0x00,0x00,0x00,0x10,0x00,
0x0E,0x00,0x00,0x08,0x10,0x00,0x1C,0x00,
0x00,0x30,0x10,0x00,0x18,0x00,0x00,0x70,
0x10,0x00,0x30,0x00,0x01,0xE0,0x10,0x00,
0x70,0x00,0x03,0x80,0x10,0x00,0x60,0x00,
0x00,0x00,0x30,0x00,0xE0,0x00,0x00,0x00,
0xF0,0x01,0xC0,0x00,0x00,0x00,0x70,0x03,
0xC0,0x00,0x00,0x00,0x10,0x07,0x80,0x00,
0x00,0x00,0x00,0x0F,0x00,0x00,0x00,0x00,
0x00,0x1E,0x00,0x00,0x00,0x00,0x00,0x3C,
0x00,0x00,0x00,0x00,0x00,0x70,0x00,0x00,
0x00,0x00,0x01,0xC0,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
};
char she48H[]={
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x04,
0x00,0x00,0x00,0x00,0x00,0x0C,0x00,0x00,
0x00,0x00,0x00,0x0E,0x00,0x00,0x00,0x00,
0x00,0x0E,0x00,0x00,0x00,0x03,0x00,0x07,
0x00,0x00,0x00,0x02,0x00,0x03,0x00,0x00,
0x00,0x02,0x00,0x00,0x00,0x00,0x00,0x02,
0x00,0x00,0xF8,0x00,0x00,0x02,0x00,0x07,
0x86,0x00,0x00,0x02,0x00,0x18,0x03,0x00,
0x00,0x02,0x00,0x00,0x07,0x80,0x00,0x03,
0xF0,0x00,0x07,0x80,0x00,0x0F,0xFC,0x00,
0x0C,0x00,0x00,0x7E,0x3F,0x80,0x00,0x00,
0x01,0xFE,0x1F,0x80,0x00,0x00,0x01,0xE2,
0x39,0x8C,0x00,0x00,0x00,0xC2,0x30,0x08,
0x00,0x00,0x00,0xC2,0x60,0x08,0x00,0x00,
0x00,0xC3,0xE0,0x08,0x60,0x00,0x00,0x7F,
0xE0,0x01,0xE0,0x00,0x00,0x3F,0x80,0x1F,
0xE0,0x00,0x00,0x1E,0x00,0x1F,0x80,0x00,
0x00,0x1E,0x00,0x1F,0x00,0x00,0x00,0x02,
0x38,0x1E,0x00,0x00,0x00,0x07,0xFC,0x1C,
0x00,0x20,0x00,0x07,0xFC,0x18,0x00,0x20,
0x00,0x1F,0x0C,0x10,0x00,0x20,0x00,0x7C,
0x04,0x10,0x00,0x60,0x01,0xF0,0x00,0x10,
0x00,0x60,0x01,0xE0,0x00,0x08,0x00,0xF0,
0x00,0x80,0x00,0x08,0x03,0xF0,0x00,0x00,
0x00,0x07,0xFF,0xF0,0x00,0x00,0x00,0x07,
0xFF,0xF0,0x00,0x00,0x00,0x03,0xFF,0xE0,
0x00,0x00,0x00,0x01,0xFF,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
};
char tun48H[]={
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x0E,0x00,0x00,0x00,0x00,0x00,0x3E,
0x00,0x00,0x00,0x00,0x00,0x7F,0x00,0x00,
0x00,0x00,0x00,0xE0,0x00,0x00,0x00,0x00,
0x03,0xC0,0x00,0x00,0x00,0x00,0x1F,0x00,
0x00,0x00,0x00,0x00,0x7C,0x00,0x00,0x00,
0x00,0x01,0xF8,0x00,0x00,0x00,0x00,0x03,
0xF8,0x00,0x40,0x00,0x00,0x00,0x06,0x07,
0xC0,0x00,0x00,0x00,0x07,0xFF,0xE0,0x00,
0x00,0x00,0x07,0xFF,0xE0,0x00,0x00,0x00,
0x0F,0xFF,0x80,0x00,0x00,0x00,0x7F,0xF8,
0x00,0x00,0x00,0x1F,0xFF,0xF8,0x00,0x00,
0x00,0x1F,0xFF,0xF8,0x00,0x00,0x00,0x1F,
0xFC,0x3C,0x00,0x00,0x00,0x0F,0xF8,0x0E,
0x00,0x00,0x00,0x04,0x70,0x07,0x00,0x00,
0x00,0x00,0x60,0x03,0x80,0x00,0x00,0x00,
0xC0,0x00,0xC0,0x00,0x00,0x01,0x80,0x00,
0x30,0x00,0x00,0x01,0x00,0x3C,0x18,0x00,
0x00,0x02,0x03,0xFF,0x0C,0x00,0x00,0x0C,
0x7F,0xFF,0x8E,0x00,0x00,0x18,0xFF,0xFF,
0xC7,0x80,0x00,0x78,0xFE,0x07,0x87,0xE0,
0x01,0xF0,0x70,0x07,0x03,0xF8,0x07,0xE0,
0x70,0x0E,0x03,0xFE,0x00,0x00,0x38,0x1E,
0x01,0xFE,0x00,0x00,0x3F,0xFE,0x00,0x0C,
0x00,0x00,0x1F,0xFE,0x00,0x00,0x00,0x00,
0x1F,0xFE,0x00,0x00,0x00,0x00,0x0F,0xFE,
0x00,0x00,0x00,0x00,0x04,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
};
char dan48H[]={
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0xFC,0x00,0x00,0x00,0x00,0x07,0xFF,
0x00,0x00,0x00,0x00,0x7F,0xC0,0x80,0x00,
0x00,0x03,0xFF,0x80,0x40,0x00,0x00,0x01,
0xF1,0x80,0x40,0x00,0x00,0x01,0x81,0x80,
0xE0,0x00,0x00,0x00,0x01,0x93,0xF0,0x00,
0x00,0x00,0x01,0xFF,0xF0,0x00,0x00,0x00,
0x21,0xFF,0xF0,0x00,0x00,0x00,0x21,0xF8,
0x00,0x00,0x00,0x00,0x61,0xC0,0x00,0x00,
0x00,0x00,0x61,0x80,0x00,0x00,0x00,0x00,
0xF3,0x00,0x00,0x00,0x00,0x00,0xFF,0x00,
0x00,0x00,0x00,0x01,0xFF,0xC0,0x00,0x00,
0x00,0x03,0xFF,0xF8,0x00,0x00,0x00,0x02,
0x00,0xFC,0x00,0x00,0x00,0x04,0x02,0x1F,
0x00,0x00,0x00,0x08,0x03,0x01,0xC0,0x00,
0x00,0x38,0x03,0x00,0x7C,0x00,0x00,0xF8,
0x07,0xF8,0x3F,0xC0,0x01,0xF0,0x3F,0xFE,
0x3F,0xF8,0x03,0xC1,0xFF,0x0F,0x1F,0xF8,
0x00,0x01,0xE3,0x0F,0x0F,0xF0,0x00,0x01,
0xC3,0x0E,0x00,0x00,0x00,0x01,0x83,0xFC,
0x00,0x00,0x00,0x00,0xC7,0xF8,0x00,0x00,
0x00,0x00,0xFF,0xF8,0x00,0x00,0x00,0x00,
0x7F,0xF0,0x00,0x00,0x00,0x00,0x3F,0x03,
0x80,0x00,0x00,0x00,0x03,0x04,0x00,0x00,
0x00,0x00,0x03,0xF8,0x00,0x00,0x00,0x00,
0x1F,0xF8,0x20,0x00,0x00,0x00,0xFF,0xFF,
0xE0,0x00,0x00,0x07,0xFF,0x81,0xE0,0x00,
0x00,0x07,0xE0,0x00,0xE0,0x00,0x00,0x03,
0x00,0x00,0x60,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
};
char zuo16H[]={
0x18,0xC0,0x18,0xC0,0x19,0x80,0x31,0xFE,
0x33,0xFE,0x76,0xC0,0xF0,0xFC,0xB0,0xFC,
0x30,0xC0,0x30,0xC0,0x30,0xFE,0x30,0xFE,
0x30,0xC0,0x30,0xC0,0x30,0xC0,0x00,0x00,
};
char zhe16H[]={
0x03,0x00,0x03,0x0C,0x1F,0xCC,0x1F,0xD8,
0x03,0x30,0xFF,0xFE,0xFF,0xFE,0x03,0x00,
0x0F,0xF8,0x3F,0xF8,0xEC,0x18,0xCF,0xF8,
0x0C,0x18,0x0F,0xF8,0x0F,0xF8,0x00,0x00,
};
char tian16H[]={
0x00,0x00,0x3F,0xFC,0x3F,0xFC,0x31,0x8C,
0x31,0x8C,0x31,0x8C,0x3F,0xFC,0x3F,0xFC,
0x31,0x8C,0x31,0x8C,0x31,0x8C,0x3F,0xFC,
0x3F,0xFC,0x30,0x0C,0x00,0x00,0x00,0x00,
};
char xue16H[]={
0x33,0x18,0x19,0x98,0x08,0xB0,0x7F,0xFC,
0x7F,0xFC,0x60,0x0C,0x1F,0xF0,0x1F,0xF0,
0x00,0xC0,0x7F,0xFC,0x7F,0xFC,0x01,0x80,
0x01,0x80,0x07,0x80,0x03,0x00,0x00,0x00,
};
char ke16H[]={
0x00,0x00,0x0C,0x18,0xFD,0x98,0xF8,0xD8,
0x18,0x58,0xFE,0x18,0xFE,0x98,0x18,0xD8,
0x3C,0x58,0x7E,0x1E,0xDB,0xFE,0x9B,0xF8,
0x18,0x18,0x18,0x18,0x18,0x18,0x00,0x00,
};
struct Food/*定义结构体存储食物的属性*/
{
int x; /* 食物的坐标 */
int y;
int yes; /* 值为0表示屏幕上没有食物,值为1表示屏幕上有食物 */
int color; /* 食物颜色 */
}food;
struct Snake/*定义结构体存储蛇的属性*/
{
int x[N]; /* 每一节蛇的坐标 */
int y[N];
int color[N];/*存储每一节蛇的颜色*/
int node; /* 蛇的节数 */
int direction; /* 蛇移动的方向 */
int life; /* 蛇的生命,如果为1,蛇死,游戏结束 */
}snake;
void init(void)/*图形驱动*/
{
int driver=DETECT,mode=0;
registerbgidriver(EGAVGA_driver);
initgraph(&driver,&mode,"");
}
void drawmat(char *mat,int matsize,int x,int y,int color)/*汉字点阵*/
{
int i,j,k,m;
m=(matsize-1)/8+1;
for(j=0;j<matsize;j++)
for(i=0;i<m;i++)
for(k=0;k<8;k++)
if(mat[j*m+i]&(0x80>>k))
putpixel(x+i*8+k,y+j,color);
}
void showword(void)
{/* 调用汉字点阵输出程序,显示标题和作者信息 */
drawmat(cai48H,48,249,-4,7);
drawmat(she48H,48,329,-4,7);
drawmat(tun48H,48,409,-4,7);
drawmat(dan48H,48,489,-4,7);
drawmat(cai48H,48,250,-5,4);
drawmat(she48H,48,330,-5,4);
drawmat(tun48H,48,410,-5,4);
drawmat(dan48H,48,490,-5,4);
/*作者 田学科*/
drawmat(zuo16H,16,515,465,7);
drawmat(zhe16H,16,530,465,7);
drawmat(tian16H,16,550,465,7);
drawmat(xue16H,16,565,465,7);
drawmat(ke16H,16,580,465,7);
}
void draw(void)/*画出四周的墙*/
{
if(color==15)
color=0;
setcolor(++color);
setlinestyle(SOLID_LINE,0,1);
for(i=30;i<=600;i+=10)
{
rectangle(i,40,i+10,49);
rectangle(i,451,i+10,460);
}
for(i=40;i<450;i+=10)
{
rectangle(30,i,39,i+10);
rectangle(601,i,610,i+10);
}
}
void prscore(void)
{/* 打印游戏分数 */
char str[10];
setfillstyle(SOLID_FILL,YELLOW);
bar(50,10,200,30);
setcolor(6);
settextstyle(0,0,2);
sprintf(str,"score:%d",score);
outtextxy(55,15,str);
}
void gameover(void)
{
cleardevice(); /* 清屏函数 */
for(i=0;i<snake.node;i++)/* 画出蛇死时的位置 */
{
setcolor(snake.color[i]);
rectangle(snake.x[i],snake.y[i],snake.x[i]+10,snake.y[i]+10);
}
prscore(); /* 显示分数 */
draw();
showword();
settextstyle(0,0,6);
setcolor(7);
outtextxy(103,203,"GAME OVER");
setcolor(RED);
outtextxy(100,200,"GAME OVER");
}
void gameplay(void)/* 玩游戏的具体过程 */
{
int flag,flag1;
randomize();
prscore();
gamespeed=50000;
food.yes=0;/* food.yes=0表示屏幕上没有食物 */
snake.life=1;/* snake.life=1表示蛇是活着的 */
snake.direction=4;/* 表示蛇的初始方向为向右 */
snake.node=2; /* 蛇的初始化为两节 */
snake.color[0]=2; /*两节蛇头初始化为绿色*/
snake.color[1]=2;
snake.x[0]=100;snake.y[0]=100;
snake.x[1]=110;snake.y[1]=100;
food.color=random(15)+1;
while(1)
{
while(1)
{
if(food.yes==0) /* 如果蛇活着 */
{
while(1)
{
flag=1;
food.yes=1;
food.x=random(56)*10+40;
food.y=random(40)*10+50;
for(i=0;i<snake.node;i++)
{
if(food.x==snake.x[i]&&food.y==snake.y[i])
flag=0;
}
if(flag) break;
}
}
if(food.yes)
{
setcolor(food.color);
rectangle(food.x,food.y,food.x+10,food.y+10);
}
for(i=snake.node-1;i>0;i--)
{
snake.x[i]=snake.x[i-1];
snake.y[i]=snake.y[i-1];
}
switch(snake.direction)
{
case 1: snake.y[0]-=10;break;
case 2: snake.y[0]+=10;break;
case 3: snake.x[0]-=10;break;
case 4: snake.x[0]+=10;break;
}
for(i=3;i<snake.node;i++)
{
if(snake.x[i]==snake.x[0]&&snake.y[i]==snake.y[0])
{
gameover();
snake.life=0;
break;
}
}
if(snake.x[0]<40||snake.x[0]>590||snake.y[0]<50||snake.y[0]>440)
{
gameover();
snake.life=0;
}
if(snake.life==0)
break;
if(snake.x[0]==food.x&&snake.y[0]==food.y)/*蛇吃掉食物*/
{
setcolor(0);
rectangle(food.x,food.y,food.x+10,food.y+10);
snake.x[snake.node]=-20;
snake.y[snake.node]=-20;
snake.color[snake.node]=food.color;
snake.node++;
food.yes=0;
food.color=random(15)+1;
score+=10;
prscore();
if(score%100==0&&score!=0)
{
for(i=0;i<snake.node;i++)/* 画出蛇 */
{
setcolor(snake.color[i]);
rectangle(snake.x[i],snake.y[i],snake.x[i]+10,snake.y[i]+10);
}
sound(200);
delay(50000);delay(50000);delay(50000);
delay(50000);delay(50000);delay(50000);
nosound();
gamespeed-=5000;
draw();
}
else
{
sound(500);
delay(500);
nosound();
}
}
for(i=0;i<snake.node;i++)/* 画出蛇 */
{
setcolor(snake.color[i]);
rectangle(snake.x[i],snake.y[i],snake.x[i]+10,snake.y[i]+10);
}
delay(gamespeed);
delay(gamespeed);
flag1=1;
setcolor(0);
rectangle(snake.x[snake.node-1],snake.y[snake.node-1],
snake.x[snake.node-1]+10,snake.y[snake.node-1]+10);
if(kbhit()&&flag1==1)/*如果没按有效键就重新开始循环*/
{
flag1=0;
key=bioskey(0);
if(key==esc)
exit(0);
else if(key==up&&snake.direction!=2)
snake.direction=1;
else if(key==down&&snake.direction!=1)
snake.direction=2;
else if(key==left&&snake.direction!=4)
snake.direction=3;
else if(key==right&&snake.direction!=3)
snake.direction=4;
}
}
if(snake.life==0)/*如果蛇死了就退出循环*/
break;
}
}
void main(void)
{
while(1)
{
color=0;
init();
cleardevice();
showword();
draw();
gameplay();
setcolor(15);
settextstyle(0,0,2);
outtextxy(200,400,"CONTINUE(Y/N)?");
while(1)
{
key=bioskey(0);
if(key==Y||key==n||key==esc)
break;
}
if(key==n||key==esc)
break;
}
closegraph();
}
③ scratch编程贪吃蛇教程
scratch编程贪吃蛇教程:
1、首先,我们新建一个项目文件。
2、我们点击添加精灵按钮。
3、在弹出的对话框中,我们选绘制角色。
8、选中橡皮擦,代码编辑区写入以下代码。
贪食蛇是一款经典的休闲游戏。有PC和手机等多平台版本,既简单又耐玩。
④ 用C语言编写 贪吃蛇的思路什么怎么样的
把你的邮箱给我,我把源程序发给你,或者你自己从网上下载,这个snake程序芹亩是NetBSD操作系统源代码的一部分,要是你能发现Bug,我先恭喜你。首巧
/者首键* $NetBSD: snake.c,v 1.9 1997/10/12 01:49:28 lukem Exp $ */
/*
* Copyright (c) 1980, 1993
* The Regents of the University of California. All rights reserved.
*
* Redistribution and use in source and binary forms, with or without
* modification, are permitted provided that the following conditions
* are met:
* 1. Redistributions of source code must retain the above right
* notice, this list of conditions and the following disclaimer.
* 2. Redistributions in binary form must reproce the above right
* notice, this list of conditions and the following disclaimer in the
* documentation and/or other materials provided with the distribution.
* 3. All advertising materials mentioning features or use of this software
* must display the following acknowledgement:
* This proct includes software developed by the University of
* California, Berkeley and its contributors.
* 4. Neither the name of the University nor the names of its contributors
* may be used to endorse or promote procts derived from this software
* without specific prior written permission.
*
* THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
* ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
* IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
* ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
* FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
* DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
* OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
* HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
* LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
* OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
* SUCH DAMAGE.
*/
#include <sys/cdefs.h>
#ifndef lint
__COPYRIGHT("@(#) Copyright (c) 1980, 1993\n\
The Regents of the University of California. All rights reserved.\n");
#endif /* not lint */
#ifndef lint
#if 0
static char sccsid[] = "@(#)snake.c 8.2 (Berkeley) 1/7/94";
#else
__RCSID("$NetBSD: snake.c,v 1.9 1997/10/12 01:49:28 lukem Exp $");
#endif
#endif /* not lint */
/*
* snake - crt hack game.
*
* You move around the screen with arrow keys trying to pick up money
* without getting eaten by the snake. hjkl work as in vi in place of
* arrow keys. You can leave at the exit any time.
*
* compile as follows:
* cc -O snake.c move.c -o snake -lm -ltermlib
*/
#include <sys/param.h>
#include <errno.h>
#include <fcntl.h>
#include <pwd.h>
#include <stdlib.h>
#include <time.h>
#include <unistd.h>
#include "snake.h"
#include "pathnames.h"
#define PENALTY 10 /* % penalty for invoking spacewarp */
#define EOT '\004'
#define LF '\n'
#define DEL '\177'
#define ME 'I'
#define SNAKEHEAD 'S'
#define SNAKETAIL 's'
#define TREASURE '$'
#define GOAL '#'
#define BSIZE 80
struct point you;
struct point money;
struct point finish;
struct point snake[6];
int loot, penalty;
int long tl, tm = 0L;
int moves;
char stri[BSIZE];
char *p;
char ch, savec;
char *kl, *kr, *ku, *kd;
int fast = 1;
int repeat = 1;
time_t tv;
char *tn;
int main __P((int, char **));
int
main(argc, argv)
int argc;
char **argv;
{
extern char *optarg;
extern int optind;
int ch, i;
(void) time(&tv);
srandom((int) tv);
while ((ch = getopt(argc, argv, "l:w:")) != -1)
switch ((char) ch) {
#ifdef notdef
case 'd':
tv = atol(optarg);
break;
#endif
case 'w': /* width */
ccnt = atoi(optarg);
break;
case 'l': /* length */
lcnt = atoi(optarg);
break;
case '?':
default:
fputs("usage: snake [-d seed] [-w width] [-l length]\n", stderr);
exit(1);
}
penalty = loot = 0;
getcap();
i = MIN(lcnt, ccnt);
if (i < 4) {
cook();
pr("snake: screen too small for a fair game.\n");
exit(1);
}
/*
* chunk is the amount of money the user gets for each $.
* The formula below tries to be fair for various screen sizes.
* We only pay attention to the smaller of the 2 edges, since
* that seems to be the bottleneck.
* This formula is a hyperbola which includes the following points:
* (24, $25) (original scoring algorithm)
* (12, $40) (experimentally derived by the "feel")
* (48, $15) (a guess)
* This will give a 4x4 screen $99/shot. We don't allow anything
* smaller than 4x4 because there is a 3x3 game where you can win
* an infinite amount of money.
*/
if (i < 12)
i = 12; /* otherwise it isn't fair */
/*
* Compensate for border. This really changes the game since
* the screen is two squares smaller but we want the default
* to be $25, and the high scores on small screens were a bit
* much anyway.
*/
i += 2;
chunk = (675.0 / (i + 6)) + 2.5; /* min screen edge */
signal(SIGINT, stop);
putpad(TI); /* String to begin programs that use cm */
putpad(KS); /* Put terminal in keypad transmit mode */
snrand(&finish);
snrand(&you);
snrand(&money);
snrand(&snake[0]);
if (ospeed < 9600 || ((!CM) && (!TA)))
fast = 0;
for (i = 1; i < 6; i++)
chase(&snake[i], &snake[i - 1]);
setup();
mainloop();
/* NOTREACHED */
return (0);
}
/* Main command loop */
void
mainloop()
{
int j, k;
for (;;) {
int c, lastc, match;
lastc = 0;
move(&you);
fflush(stdout);
if (((c = getchar() & 0177) <= '9') && (c >= '0')) {
ungetc(c, stdin);
j = scanf("%d", &repeat);
c = getchar() & 0177;
} else {
if (c != '.')
repeat = 1;
}
if (c == '.') {
c = lastc;
}
if ((Klength > 0) &&
(c == *KL || c == *KR || c == *KU || c == *KD)) {
savec = c;
match = 0;
kl = KL;
kr = KR;
ku = KU;
kd = KD;
for (j = Klength; j > 0; j--) {
if (match != 1) {
match = 0;
if (*kl++ == c) {
ch = 'h';
match++;
}
if (*kr++ == c) {
ch = 'l';
match++;
}
if (*ku++ == c) {
ch = 'k';
match++;
}
if (*kd++ == c) {
ch = 'j';
match++;
}
if (match == 0) {
ungetc(c, stdin);
ch = savec;
/* Oops! This works if we
* figure it out on second
* character. */
break;
}
}
savec = c;
if (j != 1)
c = getchar() & 0177;
}
c = ch;
}
if (!fast)
flushi();
lastc = c;
switch (c) {
case CTRL('z'):
suspend();
continue;
case EOT:
case 'x':
case 0177: /* del or end of file */
ll();
length(moves);
logit("quit");
done();
case CTRL('l'):
setup();
winnings(cashvalue);
continue;
case 'p':
case 'd':
snap();
continue;
case 'w':
spacewarp(0);
continue;
case 'A':
repeat = you.col;
c = 'h';
break;
case 'H':
case 'S':
repeat = you.col - money.col;
c = 'h';
break;
case 'T':
repeat = you.line;
c = 'k';
break;
case 'K':
case 'E':
repeat = you.line - money.line;
c = 'k';
break;
case 'P':
repeat = ccnt - 1 - you.col;
c = 'l';
break;
case 'L':
case 'F':
repeat = money.col - you.col;
c = 'l';
break;
case 'B':
repeat = lcnt - 1 - you.line;
c = 'j';
break;
case 'J':
case 'C':
repeat = money.line - you.line;
c = 'j';
break;
}
for (k = 1; k <= repeat; k++) {
moves++;
switch (c) {
case 's':
case 'h':
case '\b':
if (you.col > 0) {
if ((fast) || (k == 1))
pchar(&you, ' ');
you.col--;
if ((fast) || (k == repeat) ||
(you.col == 0))
pchar(&you, ME);
}
break;
case 'f':
case 'l':
case ' ':
if (you.col < ccnt - 1) {
if ((fast) || (k == 1))
pchar(&you, ' ');
you.col++;
if ((fast) || (k == repeat) ||
(you.col == ccnt - 1))
pchar(&you, ME);
}
break;
case CTRL('p'):
case 'e':
case 'k':
case 'i':
if (you.line > 0) {
if ((fast) || (k == 1))
pchar(&you, ' ');
you.line--;
if ((fast) || (k == repeat) ||
(you.line == 0))
pchar(&you, ME);
}
break;
case CTRL('n'):
case 'c':
case 'j':
case LF:
case 'm':
if (you.line + 1 < lcnt) {
if ((fast) || (k == 1))
pchar(&you, ' ');
you.line++;
if ((fast) || (k == repeat) ||
(you.line == lcnt - 1))
pchar(&you, ME);
}
break;
}
if (same(&you, &money)) {
loot += 25;
if (k < repeat)
pchar(&you, ' ');
do {
snrand(&money);
} while ((money.col == finish.col &&
money.line == finish.line) ||
(money.col < 5 && money.line == 0) ||
(money.col == you.col &&
money.line == you.line));
pchar(&money, TREASURE);
winnings(cashvalue);
continue;
}
if (same(&you, &finish)) {
win(&finish);
ll();
cook();
pr("You have won with $%d.\n", cashvalue);
fflush(stdout);
logit("won");
post(cashvalue, 1);
length(moves);
done();
}
if (pushsnake())
break;
}
fflush(stdout);
}
}
/*
* setup the board
*/
void
setup()
{
int i;
clear();
pchar(&you, ME);
pchar(&finish, GOAL);
pchar(&money, TREASURE);
for (i = 1; i < 6; i++) {
pchar(&snake[i], SNAKETAIL);
}
pchar(&snake[0], SNAKEHEAD);
drawbox();
fflush(stdout);
}
void
drawbox()
{
int i;
struct point p;
p.line = -1;
for (i = 0; i < ccnt; i++) {
p.col = i;
pchar(&p, '-');
}
p.col = ccnt;
for (i = -1; i <= lcnt; i++) {
p.line = i;
pchar(&p, '|');
}
p.col = -1;
for (i = -1; i <= lcnt; i++) {
p.line = i;
pchar(&p, '|');
}
p.line = lcnt;
for (i = 0; i < ccnt; i++) {
p.col = i;
pchar(&p, '-');
}
}
void
snrand(sp)
struct point *sp;
{
struct point p;
int i;
for (;;) {
p.col = random() % ccnt;
p.line = random() % lcnt;
/* make sure it's not on top of something else */
if (p.line == 0 && p.col < 5)
continue;
if (same(&p, &you))
continue;
if (same(&p, &money))
continue;
if (same(&p, &finish))
continue;
for (i = 0; i < 5; i++)
if (same(&p, &snake[i]))
break;
if (i < 5)
continue;
break;
}
*sp = p;
}
int
post(iscore, flag)
int iscore, flag;
{
short score = iscore;
int rawscores;
short uid;
short oldbest = 0;
short allbwho = 0, allbscore = 0;
struct passwd *p;
/*
* Neg uid, 0, and 1 cannot have scores recorded.
*/
if ((uid = getuid()) <= 1) {
pr("No saved scores for uid %d.\n", uid);
return (1);
}
if ((rawscores = open(_PATH_RAWSCORES, O_RDWR | O_CREAT, 0644)) < 0) {
pr("No score file %s: %s.\n", _PATH_RAWSCORES,
strerror(errno));
return (1);
}
/* Figure out what happened in the past */
read(rawscores, &allbscore, sizeof(short));
read(rawscores, &allbwho, sizeof(short));
lseek(rawscores, uid * sizeof(short), 0);
read(rawscores, &oldbest, sizeof(short));
if (!flag)
return (score > oldbest ? 1 : 0);
/* Update this jokers best */
if (score > oldbest) {
lseek(rawscores, uid * sizeof(short), 0);
write(rawscores, &score, sizeof(short));
pr("You bettered your previous best of $%d\n", oldbest);
} else
pr("Your best to date is $%d\n", oldbest);
/* See if we have a new champ */
p = getpwuid(allbwho);
if (p == NULL || score > allbscore) {
lseek(rawscores, 0, 0);
write(rawscores, &score, sizeof(short));
write(rawscores, &uid, sizeof(short));
if (allbwho)
pr("You beat %s's old record of $%d!\n",
p->pw_name, allbscore);
else
pr("You set a new record!\n");
} else
pr("The highest is %s with $%d\n", p->pw_name, allbscore);
close(rawscores);
return (1);
}
/*
* Flush typeahead to keep from buffering a bunch of chars and then
* overshooting. This loses horribly at 9600 baud, but works nicely
* if the terminal gets behind.
*/
void
flushi()
{
tcflush(0, TCIFLUSH);
}
int mx[8] = {
0, 1, 1, 1, 0, -1, -1, -1
};
int my[8] = {
-1, -1, 0, 1, 1, 1, 0, -1
};
float absv[8] = {
1, 1.4, 1, 1.4, 1, 1.4, 1, 1.4
};
int oldw = 0;
void
chase(np, sp)
struct point *sp, *np;
{
/* this algorithm has bugs; otherwise the snake would get too good */
struct point d;
int w, i, wt[8];
double v1, v2, vp, max;
point(&d, you.col - sp->col, you.line - sp->line);
v1 = sqrt((double) (d.col * d.col + d.line * d.line));
w = 0;
max = 0;
for (i = 0; i < 8; i++) {
vp = d.col * mx[i] + d.line * my[i];
v2 = absv[i];
if (v1 > 0)
vp = ((double) vp) / (v1 * v2);
else
vp = 1.0;
if (vp > max) {
max = vp;
w = i;
}
}
for (i = 0; i < 8; i++) {
point(&d, sp->col + mx[i], sp->line + my[i]);
wt[i] = 0;
if (d.col < 0 || d.col >= ccnt || d.line < 0 || d.line >= lcnt)
continue;
/*
* Change to allow snake to eat you if you're on the money,
* otherwise, you can just crouch there until the snake goes
* away. Not positive it's right.
*
* if (d.line == 0 && d.col < 5) continue;
*/
if (same(&d, &money))
continue;
if (same(&d, &finish))
continue;
wt[i] = i == w ? loot / 10 : 1;
if (i == oldw)
wt[i] += loot / 20;
}
for (w = i = 0; i < 8; i++)
w += wt[i];
vp = ((rand() >> 6) & 01777) % w;
for (i = 0; i < 8; i++)
if (vp < wt[i])
break;
else
vp -= wt[i];
if (i == 8) {
pr("failure\n");
i = 0;
while (wt[i] == 0)
i++;
}
oldw = w = i;
point(np, sp->col + mx[w], sp->line + my[w]);
}
void
spacewarp(w)
int w;
{
struct point p;
int j;
char *str;
snrand(&you);
point(&p, COLUMNS / 2 - 8, LINES / 2 - 1);
if (p.col < 0)
p.col = 0;
if (p.line < 0)
p.line = 0;
if (w) {
str = "BONUS!!!";
loot = loot - penalty;
penalty = 0;
} else {
str = "SPACE WARP!!!";
penalty += loot / PENALTY;
}
for (j = 0; j < 3; j++) {
clear();
delay(5);
apr(&p, str);
delay(10);
}
setup();
winnings(cashvalue);
}
void
snap()
{
struct point p;
if (you.line < 3) {
pchar(point(&p, you.col, 0), '-');
}
if (you.line > lcnt - 4) {
pchar(point(&p, you.col, lcnt - 1), '_');
}
if (you.col < 10) {
pchar(point(&p, 0, you.line), '(');
}
if (you.col > ccnt - 10) {
pchar(point(&p, ccnt - 1, you.line), ')');
}
if (!stretch(&money))
if (!stretch(&finish))
delay(10);
if (you.line < 3) {
point(&p, you.col, 0);
chk(&p);
}
if (you.line > lcnt - 4) {
point(&p, you.col, lcnt - 1);
chk(&p);
}
if (you.col < 10) {
point(&p, 0, you.line);
chk(&p);
}
if (you.col > ccnt - 10) {
point(&p, ccnt - 1, you.line);
chk(&p);
}
fflush(stdout);
}
int
stretch(ps)
struct point *ps;
{
struct point p;
point(&p, you.col, you.line);
if (abs(ps->col - you.col) < 6) {
if (you.line < ps->line) {
for (p.line = you.line + 1; p.line <= ps->line;
p.line++)
pchar(&p, 'v');
delay(10);
for (; p.line > you.line; p.line--)
chk(&p);
} else {
for (p.line = you.line - 1; p.line >= ps->line;
p.line--)
pchar(&p, '^');
delay(10);
for (; p.line < you.line; p.line++)
chk(&p);
}
return (1);
} else
if (abs(ps->line - you.line) < 3) {
p.line = you.line;
if (you.col < ps->col) {
for (p.col = you.col + 1; p.col <= ps->col;
p.col++)
pchar(&p, '>');
delay(10);
for (; p.col > you.col; p.col--)
chk(&p);
} else {
for (p.col = you.col - 1; p.col >= ps->col;
p.col--)
pchar(&p, '<');
delay(10);
for (; p.col < you.col; p.col++)
chk(&p);
}
return (1);
}
return (0);
}
void
surround(ps)
struct point *ps;
{
struct point x;
int j;
if (ps->col == 0)
ps->col++;
if (ps->line == 0)
ps->line++;
if (ps->line == LINES - 1)
ps->line--;
if (ps->col == COLUMNS - 1)
ps->col--;
apr(point(&x, ps->col - 1, ps->line - 1), "/*\\\r* *\r\\*/");
for (j = 0; j < 20; j++) {
pchar(ps, '@');
delay(1);
pchar(ps, ' ');
delay(1);
}
if (post(cashvalue, 0)) {
apr(point(&x, ps->col - 1, ps->line - 1), " \ro.o\r\\_/");
delay(6);
apr(point(&x, ps->col - 1, ps->line - 1), " \ro.-\r\\_/");
delay(6);
}
apr(point(&x, ps->col - 1, ps->line - 1), " \ro.o\r\\_/");
}
void
win(ps)
struct point *ps;
{
struct point x;
int j, k;
int boxsize; /* actually diameter of box, not radius */
boxsize = fast ? 10 : 4;
point(&x, ps->col, ps->line);
for (j = 1; j < boxsize; j++) {
for (k = 0; k < j; k++) {
pchar(&x, '#');
x.line--;
}
for (k = 0; k < j; k++) {
pchar(&x, '#');
x.col++;
}
j++;
for (k = 0; k < j; k++) {
pchar(&x, '#');
x.line++;
}
for (k = 0; k < j; k++) {
pchar(&x, '#');
x.col--;
}
}
fflush(stdout);
}
int
pushsnake()
{
int i, bonus;
int issame = 0;
/*
* My manual says times doesn't return a value. Furthermore, the
* snake should get his turn every time no matter if the user is
* on a fast terminal with typematic keys or not.
* So I have taken the call to times out.
*/
for (i = 4; i >= 0; i--)
if (same(&snake[i], &snake[5]))
issame++;
if (!issame)
pchar(&snake[5], ' ');
for (i = 4; i >= 0; i--)
snake[i + 1] = snake[i];
chase(&snake[0], &snake[1]);
pchar(&snake[1], SNAKETAIL);
pchar(&snake[0], SNAKEHEAD);
for (i = 0; i < 6; i++) {
if (same(&snake[i], &you)) {
surround(&you);
i = (cashvalue) % 10;
bonus = ((rand() >> 8) & 0377) % 10;
ll();
pr("%d\n", bonus);
delay(30);
if (bonus == i) {
spacewarp(1);
logit("bonus");
flushi();
return (1);
}
if (loot >= penalty) {
pr("You and your $%d have been eaten\n",
cashvalue);
} else {
pr("The snake ate you. You owe $%d.\n",
-cashvalue);
}
logit("eaten");
length(moves);
done();
}
}
return (0);
}
int
chk(sp)
struct point *sp;
{
int j;
if (same(sp, &money)) {
pchar(sp, TREASURE);
return (2);
}
if (same(sp, &finish)) {
pchar(sp, GOAL);
return (3);
}
if (same(sp, &snake[0])) {
pchar(sp, SNAKEHEAD);
return (4);
}
for (j = 1; j < 6; j++) {
if (same(sp, &snake[j])) {
pchar(sp, SNAKETAIL);
return (4);
}
}
if ((sp->col < 4) && (sp->line == 0)) {
winnings(cashvalue);
if ((you.line == 0) && (you.col < 4))
pchar(&you, ME);
return (5);
}
if (same(sp, &you)) {
pchar(sp, ME);
return (1);
}
pchar(sp, ' ');
return (0);
}
void
winnings(won)
int won;
{
struct point p;
p.line = p.col = 1;
if (won > 0) {
move(&p);
pr("$%d", won);
}
}
void
stop(mmy)
int mmy;
{
signal(SIGINT, SIG_IGN);
ll();
length(moves);
done();
}
void
suspend()
{
ll();
cook();
kill(getpid(), SIGTSTP);
raw();
setup();
winnings(cashvalue);
}
void
length(num)
int num;
{
pr("You made %d moves.\n", num);
}
void
logit(msg)
const char *msg;
{
FILE *logfile;
time_t t;
if ((logfile = fopen(_PATH_LOGFILE, "a")) != NULL) {
time(&t);
fprintf(logfile, "%s $%d %dx%d %s %s",
getlogin(), cashvalue, lcnt, ccnt, msg, ctime(&t));
fclose(logfile);
}
}
⑤ scratch贪吃蛇制作教程
scratch贪吃蛇制作教程如下:
1、游戏工亮轮作过程。键盘主要控制贪吃蛇的头部移动,尾巴是沿着轨迹移动就行。贪吃蛇的身体,是用程序画笔模块敬差信画出来的。如果头部吃到食物,就给游戏分数加分。
6、最终游戏效果:点击“绿色旗子”开始游戏,按下键盘的方向键,控制贪吃蛇移动。
吃到食物时,变量“游戏分数”就会加1分。
⑥ 利用解释型语言编写的贪吃蛇程序什么意思
用C语言来实现也是一个好玩的事情。这个游戏我写完后放在知乎,竟然点赞的人数超级多。我觉得大家喜欢,一个方面是因为写得简单,大家都能看得懂,一个可扩展性还是非常强的。
我试了说一下这个代码 核心的三个函数
menu();
setup();
draw();
menu用来设置菜单,也就是我们一运行看到的那个。setup用来设置参数,我们需要设置高度和宽度,还有分搜清橘数,食物的位置。draw也就是画,也就是画整个画面。
还有一个枚举类型 这个结构体用来设置蛇的几个状态,我觉得这个也是面向对象编程的一个思想,把蛇的状态都封装成一个枚举类型。
typedef enum
{
STOP = 0,
LEFT,
RIGHT,
UP,
DOWN
}Direction;
还有
/*判断贪吃蛇的长度*/
void logic()
这个函数,这个函数应该是整个贪吃蛇的精髓了,要理解代码怎么把蛇给连接起来。用了点巧妙的东西。
来看这里面的关键代码
/*把上一个位置记下*/
int lastX = tailX[0];
int lastY = tailY[0];
int last2X, last2Y;
/*重新获取当前的位置*/
tailX[0]=x;
tailY[0]=y;
int i=0;
/*遍历整条蛇的长度 把 0 的位置空出来正闷,其余蛇的位置往后面的空间移动*/
for(i=1; i ntail;i++)
{
last2X = tailX[i];
last2Y = tailY[i];
tailX[i]=lastX;
tailY[i]=lastY;
lastX = last2X;
lastY = last2Y;
}
lastX lastY 用来存上一次的蛇头的位置。后面的 for 循环,通过tail 蛇的长度,把蛇上个状态给保存到数组tailX tailY里面。
完整代码
#include stdio.h
#include stdlib.h
#include stdbool.h
#include Windows.h
#include time.h
#include conio.h /*键盘输入获取*/
bool gameOver;
bool stop = false;
bool hit = false;
/*游戏的边框大小*/
const int width = 50;
const int height = 20;
/*蛇的坐标,食物的坐标还有分数*/
int x,y,fruitX,fruitY,score;
/*蛇每个点的坐标*/
int tailX[200],tailY[200];
/*蛇的默认长度*/
int ntail=3;
typedef enum
{
STOP = 0,
LEFT,
RIGHT,
UP,
DOWN
}Direction;
Direction Dir;
/*开始菜单*/
void menu()
{
int a;
printf( ------------------------------------------------------------------\n
printf( | 贪吃蛇游戏 |\n
printf( | 1) 新游戏 |\n
printf( | 2) 开始边界 |\n
printf( | 3) 退出游戏 |\n
printf( ------------------------------------------------------------------\n
printf( ---- 请输入你的选择:
scanf( %d ,
}
/*初始化状态*/
void setup()
{
gameOver = false;
/*根据当前时间设置“随机数种子”*/
srand(time(NULL));
Dir = STOP;
/*贪吃蛇的位置,固定在中间*/
x= width/2;
y= height/2;
/*食物的位置,位置是随机的*/
fruitX = rand()%width;
fruitY = rand()%height;
score = 0;
}
/*绘制界面世团*/
void draw()
{
if(stop == true)
{
return;
}
system( cls /*清除屏幕*/
printf( 分数:%d ,score);
printf( \n
/*第一行*/
int i;
for(i= 0 ;i width+1;i++)
{
printf( -
}
printf( \n
/*画中间的画面*/
int p;
for(p= 0 ;p height;p++)/*高度*/
{
int q;
for(q= 0 ;q width;q++)/*宽度*/
{
/*第一行最后已给字符*/
if(q==0 || q==width-1)
{
printf( |
}
if(p == fruitY q == fruitX)/*食物的随机坐标*/
{
printf( O
}
else
{
int k=0;
bool print = false;
/*贪吃蛇的长度 默认长度是 3*/
for(k=0;k ntail;k++)
{
if(tailX[k]==q tailY[k]==p)
{
printf( *
print = true;
}
}
/*如果这个位置打印了 * 就不要打印空格了*/
if(!print)
{
printf(
}
}
}
printf( \n
}
/*最后一行*/
int j;
for(j= 0 ;j width+1;j++)
{
printf( -
}
}
/*按键输入控制*/
void input()
{
if(_kbhit())
{
/*获取键盘的输入字符*/
switch(_getch())
{
case 4 :
case 75:/*左键*/
Dir = LEFT;
hit= true;
break;
case 8 :
case 72:/*上键*/
Dir = UP;
hit= true;
break;
case 6 :
case 77:/*右键*/
Dir = RIGHT;
hit= true;
break;
case 2 :
case 80:/*向下键盘键 */
Dir = DOWN;
hit= true;
break;
case x :
case 27:/*ESE*/
gameOver = true;
break;
case 32:/*空格 暂停键*/
stop = !stop;
break;
}
}
else if(!hit stop == false)/*如果没有改变方向*/
{
x++;
}
}
/*判断贪吃蛇的长度*/
void logic()
{
if(stop == true)
{
return;
}
/*把上一个位置记下*/
int lastX = tailX[0];
int lastY = tailY[0];
int last2X, last2Y;
/*重新获取当前的位置*/
tailX[0]=x;
tailY[0]=y;
int i=0;
/*遍历整条蛇的长度 把 0 的位置空出来,其余蛇的位置往后面的空间移动*/
for(i=1; i ntail;i++)
{
last2X = tailX[i];
last2Y = tailY[i];
tailX[i]=lastX;
tailY[i]=lastY;
lastX = last2X;
lastY = last2Y;
}
/*根据方向来改变x y 的值*/
switch(Dir)
{
case UP:
y--;
break;
case DOWN:
y++;
break;
case LEFT:
x--;
break;
case RIGHT:
x++;
break;
}
if(x 0 || width x || y 0 || height y)
{
gameOver = true;
/*清除屏幕*/
system( cls
printf( ------------------------------------------------------------------\n
printf( | |\n
printf( | |\n
printf( | 游戏结束 |\n
printf( | |\n
printf( | |\n
printf( ------------------------------------------------------------------\n
}
if(x==fruitX y==fruitY)
{
/*吃了一个食物,蛇的长度增加1*/
ntail++;
score+=10;
/*更新下一个食物的位置*/
fruitX = rand()%width;
fruitY = rand()%height;
}
}
int main()
{
#if 0
while(1)
{
printf( %d\n ,_getch());
}
#endif
menu();
setup();
draw();
/*循环画贪吃蛇的界面*/
while(!gameOver)
{
draw();
input();
logic();
Sleep(70);
}
return 0;
}
上面这段代码直接在Dev C++上面应该是可以运行的,很多人在知乎上私信问我,为什么我的贪吃蛇执行不了呢,可能就是平台不同,少了这个头文件,少了那个头文件,但是你为什么不能跟我一样,用Dev C++呢,轻量级,简单。代码的精髓是什么?我认为精髓一定是思想,不是你写了多少行代码,用了什么高端的IDE。
我自认为我的注释已经写得不错了,所以就没有什么好说明的了吧,有不明白的把代码过一下,至于屏幕刷新这个东西,如果只是用时间刷新就会闪屏,所以出现了一个双缓存,把要显示的东西送到一个buff里面去,另一个buff用来显示,这样就可以保证不会出现闪屏。除了写贪吃蛇,可以用这个方法写其他小程序,挺有意思的。
在知乎上,发起了一个C语言 100 行代码之内实现贪吃蛇的问题。我觉得很不错,里面很多同学的回复都非常赞,特别是叶大神的回复。
0142235ea7197f4e1d7ClTovj.png
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C语言for回圈设计输入一个正整数,求它的各位数字之和及位数 例如234的各位数之和为9 位数是3以下文字资料是由(历史新知网www.lishixin.com)小编为大家搜集整理后发布的内容,让我们赶快一起来看一下吧!C语言for回圈设计输入一个正整数,求它的各位数字之和及位数 例如234的各位数之和为9 位数是3同意二楼,但得改一下#includeint main(int argc, ch...
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该楼层疑似违规已被系统折叠隐藏此楼查看此楼#include int game[3][3]={0};void Show(int turn,int x,int y){int i=0,j=0;if(x>0 && y>0){if(turn%2){game[x-1][y-1]=1;}else{game[x-1][y-1]=-1;}}for(i=0;i<3;++i){for...
⑦ java 编写贪吃蛇游戏的大体思路是什么
楼主没有看到蛇移动的本质,蛇虽然是分成很多块,但他们还是一个整体,每一块的移动都和上一块有关,所以不需要对每一块都进行判断。x0dx0a原理:x0dx0a把蛇身体的每一块看成一个对象(对象存储该块的坐标和相关信息),作为节点存储在线性链表中,再设置一个变量标志蛇的方向(通过按键可以改变)。一般人都是让每一个节点等于他指向的下一个节点,并让头节点改变位置来实差局现转弯和移动,这个算法复杂度太高(O(n)),实际上只要做两步操作,插入一个头节点,删除一个尾节点就可以了,新插入的头节点位置根据蛇当前的方向决定 用一个数组将蛇头的行径记录下来,然后第二段的下一个方格设置为蛇头走过的方格,这样子蛇走过的路径都是前一段走过的,最后将跟着蛇头走了,比如x0dx0a蛇身的路径x0dx0a for(int i=snakeLength-1;i>0;i--){x0dx0arows[i]=rows[i-1];//依次将蛇前面一段走过行的路段赋值给蛇的下一段x0dx0acols[i]=cols[i-1];//依次将蛇前面一段走过列的路段赋值给蛇的下一段x0dx0a}x0dx0afor(int i=1;i ⑧ 如何用慧编程做贪吃蛇代码
用慧编程做贪吃蛇代码过程如下: ⑨ c语言 贪吃蛇 程序 基本思路: 蛇每吃一个食物蛇身子就增加一格,用UP, DOWN, LEFT, RIGHT控制蛇头的运动,而蛇身子跟着蛇头走,每后一格蛇身子悉薯桥下一步走到上一格蛇身子的位置睁猛,以此类推。 #include <stdio.h> #include <conio.h> #include <windows.h> #define BEG_X2 #define BEG_Y1 #define WID20 #define HEI20 HANDLE hout; typedef enum {UP, DOWN, LEFT, RIGHT} DIR; typedef struct Snake_body { COORD pos;//蛇身的位置 struct Snake_body *next;//下一个蛇身 struct Snake_body *prev;//前一个蛇身 }SNAKE, *PSNAKE; PSNAKE head = NULL;//蛇头 PSNAKE tail = NULL;//蛇尾 //画游戏边框的函数 void DrawBorder() { int i, j; COORD pos = {BEG_X, BEG_Y}; for(i = 0; i < HEI; ++i) { SetConsoleCursorPosition(hout, pos); for(j = 0; j < WID; ++j) { if(i == 0)//第一行 { if(j == 0) printf("┏"); else if(j == WID - 1) printf("┓"); else printf("━"); } else if(i == HEI - 1)//最后一行 { if(j == 0) printf("┗"); else if(j == WID - 1) printf("┛"); else printf("━"); } else if(j == 0 || j == WID - 1)//第一列或最后一列 printf("┃"); else printf(" "); } ++pos.Y; } } //添加蛇身的函数 void AddBody(COORD pos) { PSNAKE pnew = (PSNAKE)calloc(1, sizeof(SNAKE)); pnew->pos = pos; if(!head) { head = tail = pnew; } else { pnew->next = head;//新创建蛇身的next指向原先的蛇头 head->prev = pnew;//原先的蛇头的prev指向新创建的蛇身 head = pnew;//把新创建的蛇身作为新的手和蛇头 } SetConsoleCursorPosition(hout, head->pos); printf("◎"); } //蛇身移动的函数 void MoveBody(DIR dir) { PSNAKE ptmp; COORD pos = head->pos; switch(dir) { case UP: if(head->pos.Y > BEG_Y + 1) --pos.Y; else return; break; case DOWN: if(head->pos.Y < BEG_Y + HEI - 2) ++pos.Y; else return; break; case LEFT: if(head->pos.X > BEG_X + 2) pos.X -= 2; else return; break; case RIGHT: if(head->pos.X < BEG_X + (WID - 2) * 2) pos.X += 2; else return; break; } AddBody(pos);//添加了一个新的蛇头 ptmp = tail;//保存当前的蛇尾 tail = tail->prev; if(tail) tail->next = NULL; SetConsoleCursorPosition(hout, ptmp->pos); printf(" "); free(ptmp); } int main() { int ctrl; DIR dir = RIGHT;//初始蛇的方向是向右的 COORD pos = {BEG_X + 2, BEG_Y + HEI / 2}; system("color 0E"); system("mode con cols=90 lines=30"); hout = GetStdHandle(STD_OUTPUT_HANDLE); printf(" ------------贪吃蛇的移动------------"); DrawBorder(); //自定义几个蛇的身体 AddBody(pos); pos.X += 2; AddBody(pos); pos.X += 2; AddBody(pos); pos.X += 2; AddBody(pos); pos.X += 2; AddBody(pos); pos.X += 2; AddBody(pos); pos.X += 2; AddBody(pos); //控制蛇的移动 while(ctrl = getch()) { switch(ctrl) { case 'w': if(dir == DOWN) continue; dir = UP; break; case 's': if(dir == UP) continue; dir = DOWN; break; case 'a': if(dir == RIGHT) continue; dir = LEFT; break; case 'd': if(dir == LEFT) continue; dir = RIGHT; break; case 'q': return 0; } MoveBody(dir); } return 0; } (9)贪吃蛇编程思路扩展阅读: 实现逻辑 1,可以设置光标,就能实现制定位置打印制定符号。 2,涉及一个结构体,包含两个元素坐标元素和一个结构体指针。 3,结构体串联形成链表,遍历获取成员坐标,打印符号得到蛇身。 4,不断的加头,去尾,重新遍历坐标,再打印形成蛇的移动。 5,食物产生的位置判定,不能越界,也不能与蛇身体重合。 6,蛇的转向判定,一条规则,不允许倒退。 7,转向的实现,跟行进方向决定新的关节坐标(当前头的上下左右) 8,死亡检测,是否头节点坐标是否与墙壁重合,是否与身体其他关节重合。 9,加速减速,设置刷新休眠时间实现。 ⑩ java贪吃蛇技术选型怎么写的 Java贪吃蛇技术选型一般需要考虑以下几点: 开发平台:需要选择适用于Java语言的开发平台,如Eclipse、IntelliJ IDEA等。 编程语言:需要选择Java语言来开发贪吃蛇游戏。 框架和库:可以使用Java中的Swing框架和AWT库来开发图形界面,并使用Java多线程编程技术来实现游戏的实时动态效果。 算法和数据结构:可以使用队列或链表等数据结构来存储贪吃蛇的身体,并使用类似贪心算法的思想来决定贪吃蛇的下一步移动方向。 编码风格和规范:需要遵循Java的编码风格和规范,确保代码的可读性和可维护性。 希望以上内容能够帮助您了解Java贪吃蛇技术选型。如果您有其他问题,欢迎随时告诉我,我会尽力为您解答。
1、我们需要建立四个头文件,然后分别设置蛇的状态,上下左右,这是蛇能够有方向可走的前提,然后我们再设置蛇身的节点,定义一个简单的函数,这样蛇的全身以及他的行走方向就弄完了。
2、贪吃蛇不能穿墙代码。
3、第二步,一个函数这个函数的目的是贪吃蛇不能穿墙,很简单的代码分别设置长宽的最大位移,在内部范围内设置为一即可通过,否则不能穿墙。贪吃蛇随机生成一个食物。
4、设置一个随机函数。这样贪吃蛇代码就做好了。
慧编程是一款面向STEAM教育领域的积木式和代码编程软件,基于图形化编程开发。