转化正态分布python

A. python 怎么求标准正态分布某个值

示例：

1、from numpy import *;

2、def rand_Matrix():

3、randArr=random.randn(2,3);

4、randMat=mat(randArr);

5、return randMat;

一种结果如下:

1、matrix([[ 0.3150869 , -0.02041996, -0.15361071],

2、[-0.75507988, 0.80393683, -0.31790917]])

(1)转化正态分布python扩展阅读

Python正态分布概率计算方法：

def st_norm(u):

'''标准正态分布'''

import math

x=abs(u)/math.sqrt(2)

T=(0.0705230784,0.0422820123,0.0092705272,

0.0001520143,0.0002765672,0.0000430638)

E=1-pow((1+sum([a*pow(x,(i+1))

for i,a in enumerate(T)])),-16)

p=0.5-0.5*E if u<0 else 0.5+0.5*E

return(p)

def norm(a,sigma,x):

'''一般正态分布'''

u=(x-a)/sigma

return(st_norm(u))

while 1:

'''输入一个数时默认为标准正态分布

输入三个数(空格隔开)时分别为期望、方差、x

输入 stop 停止'''

S=input('please input the parameters: ')

if S=='stop':break

try:

L=[float(s) for s in S.split()]

except:

print('Input error!')

continue

if len(L)==1:

print('f(x)=%.5f'%st_norm(L[0]))

elif len(L)==3:

print('f(x)=%.5f'%norm(L[0],L[1],L[2]))

else:

print('Input error!')

B. 如何用python语言，产生某一区间内的正态分布的100个随机数

import matplotlib.pyplot as plt
import scipy.stats as stats

lower, upper = 3.5, 6
mu, sigma = 5, 0.7
X = stats.truncnorm(
(lower - mu) / sigma, (upper - mu) / sigma, loc=mu, scale=sigma)
N = stats.norm(loc=mu, scale=sigma)

fig, ax = plt.subplots(2, sharex=True)
ax[0].hist(X.rvs(10000), normed=True)
ax[1].hist(N.rvs(10000), normed=True)
plt.show()

C. 如何将已知数据用python写成正态分布并且画图

importnumpyasnp
importmatplotlib.pyplotasplt

y=[2,5,7,10,16,23,20,16,9,6,6,3,1,1]
x=[59,60,61,62,63,64,65,66,67,68,69,70,71,72]
fig,ax=plt.subplots()
ax.bar(x,y,0.3,alpha=0.5,color='b',label='abc')
plt.axis([55,75,0,25])
ax.set_xlabel('XXX')
ax.set_ylabel('YYY')
ax.set_title('ABC')
ax.legend()
fig.tight_layout()
plt.show()