java编程习题集

⑴ 有关java编程题目

按照题目要求编写的圆,圆锥和测试类的Java程序如下

Test.java文件内容如下

class Circle{

private double r;

private String color;

public Circle(double r){

this.r=r;

}

public double area(){

return Math.PI*r*r;

}

public double perimeter(){

return Math.PI*2*r;

}

public double getR(){

return this.r;

}

public void setR(double r){

this.r=r;

}

public String getColor(){

return this.color;

}

public void setColor(String color){

this.color=color;

}

public String toString(){

return "圆的半径为"+r+",颜色为"+color;

}

}

class Cone{

private Circle c;

private double h;

private String color;

public Cone(Circle c,double h){

this.c=c;

this.h=h;

}

public double volume(){

return 1.0/3*c.area()*h;

}

public Circle getCircle(){

return this.c;

}

public void setCircle(Circle c){

this.c=c;

}

public double getH(){

return this.h;

}

public void setH(double h){

this.h=h;

}

public String getColor(){

return this.color;

}

public void setColor(String color){

this.color=color;

}

public String toString(){

return "圆锥的底面积为"+c.area()+",高为"+h+",颜色为"+color;

}

}

public class Test{

public static void main(String[] args){

Circle circle1=new Circle(2.5);

circle1.setColor("红色");

System.out.println(circle1.toString());

System.out.println("圆的面积为"+circle1.area());

System.out.println("圆的周长为"+circle1.perimeter());

Cone circlar1=new Cone(circle1,2.7);

circlar1.setColor("蓝色");

System.out.println(circlar1.toString());

System.out.println("圆锥的体积为"+circlar1.volume());

}

}

⑵ 五道java语言描述的数据结构编程题，请求给予详细解答

第一题：

//使用集合提供的工具方法
public static List<Integer> merge(List<Integer> a, List<Integer> b) {
//a,b not null
//全部放到一个set里面，使得元素合并
Set<Integer> set = new HashSet<Integer>(a);
set.addAll(b);
//将set里面的元素放到列表再转为数组
Integer[] array = new ArrayList<Integer>(set).toArray(new Integer[1]);
//升序排序
Arrays.sort(array);
//将排序后的数组转为list
return Arrays.asList(array);
}

//自己写的算法， a为升序列表，b为降序列表
public static List<Integer> merge2(List<Integer> a, List<Integer> b) {
//a,b not null
int aSize = a.size();
int bSize = b.size();
List<Integer> result = new ArrayList<Integer>();
int aIndex = 0;// 升序列表从首位开始
int bIndex = bSize - 1;// 降序列表从末尾开始
int aEl;
int bEl;
// 循环终止条件为: a 或者 b 列表遍历完
while (aIndex < aSize && bIndex >= 0) {
aEl = a.get(aIndex);
bEl = b.get(bIndex);
if (aEl < bEl) {
result.add(aEl);
aIndex++;
} else {
result.add(bEl);
bIndex--;
}
}
// 将某个未遍历完的列表中的元素添加到结果(包括了任意一个列表为空列表的情况)
if (aIndex < aSize) {
for (int i = aIndex; i < aSize; i++) {
result.add(a.get(i));
}
}
else if (bIndex > 0) {
for (int i = bIndex; i >= 0; i--) {
result.add(b.get(i));
}
}
return result;
}

⑶ 100分,几道简单的Java编程题，帮忙解决一下！

不是我牛叉
以前有过类似的练习
修改了一陪册乎下就姿裤发了
我也同意楼下的观点 自己动手做一下
有什么不明白的可以参考我的这个
也许你有更好的解决方法
1.
import java.util.Scanner;
public class Test_If_Switch
{
public static void main(String[] args) {
System.out.println("输入一个数字:");
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
System.out.println("方法1:"+methodl(x));
System.out.println("方法2:"+method2(x));
}
static int methodl(int x)
{
int result = 0;
if(x<0)
result = 2*x-1;
else if(x>=0&&x<3)
result = 3*x+5;
else if(x>=3&&x<5)
result = x+1;
else if(x>=5&&x<10)
result=5*x-3;
else if(x>=10)
result = 7*x+2;
return result;
}

static int method2(int x)
{
int result = 0;
switch(x)
{
case 0:
case 1:
case 2:result = 3*x+5;break;
case 3:
case 4:result = x+1;break;
case 5:
case 6:
case 7:
case 8:
case 9:result=5*x-3;break;
case 10:result = 7*x+2;break;
default:result = 2*x-1;break;
}
return result;
}
}

2.
import java.util.Scanner;

public class Test_Tn {
public static void main(String[] args) {
System.out.println("输入一个数字:");
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
System.out.println("第"+x+"项的值为:"+method(x));

}

static long static method(int n) {
long Tn = 0;
if (x == 1)
Tn = 1;
else
Tn = method(x - 1) + x;
return Tn;
}
}

3.
public class test
{
public static void main (String args[])
{
int n=100;
while(n<=1000)
{
int i,j,k;
i=n/100;
j=(n-i*100)/10;
k=n%10;
if((Math.pow(i, 3)+Math.pow(j, 3)+Math.pow(k, 3))==n)

System.out.print(n+String.valueOf('\t'));
n++;
}
}
}

4.
public class Money {
public static void main(String[] args)
{
int a = 100,b = 50, c =10;
for(int i =5;i<=8;i++)
for(int j = 0;j<=6;j++)
for(int k = 0;k<30;k++)
{
if(a*i+b*j+c*k==800)
System.out.println("芦悉100元"+i+"张"+"50元"+j+"张"+"10元"+k+"张");
}

}
}